Answer and Explanation:
Iodine have lower atomic mass than tellurium even though the atomic number of iodine is more than the atomic number of tellurium
This is because the atomic weight of any element is the sum of number of proton and number of neutron, even though the number of proton in iodine is more so but the number of neutron is less as compared to tellurium which makes the tellurium of high atomic mass
Answer:

Explanation:
Hello there!
In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:

Thus, we solve for the molarity of the acid to obtain:

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Thomson proposed this idea. Rutherford disproved it when he shot alpha particles at a gold sheet and they bounced back at him, proving that the alpha particles bounced off something aka the nucleus.
D.
A.) The conversion factor is 1 amu =

To know how many amu in

grams of neutrons:

=1.00811 amu
b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.

=

c.) How many amu in 6.492x10^-23g potassium?

= 39.0957 amu
Answer:
- 0.0249% Sb/cm

Explanation:
Given that:
One surface contains 1 Sb atom per 10⁸ Si atoms and the other surface contains 500 Sb atoms per 10⁸ Si atoms.
The concentration gradient in atomic percent (%) Sb per cm can be calculated as follows:
The difference in concentration = 
The distance
= 0.2-mm = 0.02 cm
Now, the concentration of silicon at one surface containing 1 Sb atom per 10⁸ silicon atoms and at the outer surface that has 500 Sb atom per 10⁸ silicon atoms can be calculated as follows:

= - 0.0249% Sb/cm
b) The concentration
of Sb in atom/cm³ for the surface of 1 Sb atoms can be calculated by using the formula:

Lattice parameter = 5.4307 Å; To cm ; we have
= 

= 
The concentration
of Sb in atom/cm³ for the surface of 500 Sb can be calculated as follows:

= 
= 
Finally, to calculate the concentration gradient


