Ask question

Ask question

All categories

soldi70 [24.7K]

2 years ago

3

Scott has 1/3 as many computer games as Anish, and Anish has 1/2 as many games as Nick. Together they have 140 games. How many d

o they have each?
Scott has.......
Anish has.......
Nick has........

1 answer:

qaws [65]2 years ago

4 0

Anish has 42 games, Scott has 14 games, and Nick has 84 games

You might be interested in

Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a differen

Anna007 [38]

Answer:

5 miles.

Step-by-step explanation:

Consider the question: Jinghua hiked 4 1/2 miles through the woods in 2 1/4 hours. She hiked the return trip at the same average rate but by a different route taking 2 1/2 hours. How many miles did Jinghua hike on the return trip ?

First of all, we will find Jinghua's speed using given information as:

$\text{Speed}=\frac{\text{Distance}}{\text{Time}}$

Convert mixed fractions into improper fractions:

$4\frac{1}{2}\Rightarrow \frac{9}{2}$

$2\frac{1}{4}\Rightarrow \frac{9}{4}$

$\text{Jinghua's speed}=\frac{\frac{9}{2}\text{ Miles}}{\frac{9}{4}\text{ Hours}}$

Using property $\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{ad}{bc}$ :

$\text{Jinghua's speed}=\frac{9*4\text{ Miles}}{9*2\text{ Hours}}$

$\text{Jinghua's speed}=\frac{2\text{ Miles}}{\text{ Hour}}$

We know that distance is equal to the product of speed and time.

$\text{Distance}=\text{Speed}\times\text{Time}$

Since we have been given that Jingua hiked the return trip at the same average rate, so distance covered by her on return trip would be speed (2 miles her hour) times given time (2 1/2 hours).

$\text{Distance covered by Jingua on return trip}=\frac{2\text{ Miles}}{\text{ Hour}}\times 2\frac{1}{2}\text{ Hours}$

$\text{Distance covered by Jingua on return trip}=2\text{ Miles}\times \frac{5}{2}$

$\text{Distance covered by Jingua on return trip}=5\text{ Miles}$

Therefore, Jingua hiked 5 miles on her return trip.

8 0

2 years ago

3. Adrian kept an eye on the basketball game score by looking online every 10 minutes. Over the course of

Montano1993 [528]

Answer:

3. Adrian kept an eye on the basketball game score by looking online every 10 minutes. Over the course of

2 hours, 4 times Adrian’s favorite team was ahead by 3 points, and 4 times Adrian’s favorite team was behind

by 4 points. All other times, the two teams were tied.

(a) What is the average score of Adrian’s favorite team relative to its opponent using the observations

Adrian made during the game? Show your work neatly.

(b) Explain what this value means about Adrian’s favorite team’s performance

Step-by-step explanation:

7 0

1 year ago

How far should Galileo walk up the inclined plane?

sergejj [24]

Answer:

Step-by-step explanation:

150/x=sin 15

x=150/sin 15 ≈579.56 m

4 0

2 years ago

A gene can be either type A or type B, and it can be either dominant or recessive. If the gene is type B, then there is a probab

WARRIOR [948]

Answer: The probability that a gene is of type A is 0.29.

Step-by-step explanation:

Let A be the event of type A.

Let B be the event of type B.

Let D be the event of dominant.

So, P(B and D) = 0.22

P(D|B)=0.31

So, Using the conditional probability, we get that

$P(B|D)=\dfrac{P(B\cap D)}{P(B)}\\\\0.31=\dfrac{0.22}{P(B)}\\\\P(B)=\dfrac{0.22}{0.31}=0.71$

So, the probability that a gene is of type A is given by

$P(A)=1-P(B)=1-0.71=0.29$

Hence, the probability that a gene is of type A is 0.29.

8 0

2 years ago

Read 2 more answers

Write the standard form of the line that contains a slope of and y-intercept of 3. Include your work in your final answer. Type

coldgirl [10]

Y=mx + b
m= slope
b= y intercept

y=3x + 3

7 0

2 years ago

Read 2 more answers