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Elis [28]
2 years ago
11

A third grader decided to breed guinea pigs for her school science project. She went to a pet store and bought a male with smoot

h black fur and a female with rough white fur. She wanted to study the inheritance patterns of these traits. A cross between these two parents resulted in two litters with a total of 15 F1 progeny, all of which were rough and black. Soon, the F1 litters began to produce F2 progeny, and before long the child had 125 F2 guinea pigs. 8 had smooth white coats, 25 had smooth black coats, 23 were rough and white, and 69 were rough and black. Draw the Punnett Square for the cross between the rough black F1s. How are the coat color and texture traits inherited

Biology
1 answer:
Step2247 [10]2 years ago
7 0

Answer:

The F₁ generation had all black and rough fur. Thus, black is dominant over white and rough is dominant over smooth.

Let us consider the two genes B and R for fur color and quality of fur respectively.

In gene B, B is the dominant allele which codes for black color and b is a recessive allele which codes for white color (when present in homozygous condition).

Similarly, in gene R, R is a dominant allele which codes for roughness and r being a recessive allele which codes for smooth fur (when present in homozygous condition).

So, the genotype of parents would be rrBB (smooth and black fur) and RRbb(rough and white fur).

The cross would result in the production of offspring all with rough and black fur that is, RrBb.

The selfing of F₁ generation would result in the production of offspring with four types of phenotypes; smooth white coats, smooth black coats, rough and white, and rough and black.

It shows that the alleles for the coat color and texture traits are inherited independently of each other.

The same is explained with the help of Punnett square in the below attachment.

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Answer:

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<u>2- The graph helps in selecting the best marketing strategy to improve sales</u>

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6 0
2 years ago
You work for the WWF. Write a letter to the mayor of a small farm town to explain why this town is experiencing erosion, and why
horrorfan [7]

The letter should contain concerns about the causes and ill effects of erosion.

<h3><u>Explanation</u>:</h3>

Sir,

I am very sad to inform you that the town of Hariharanpur is suffering from continuous erosion for the last 3 years. Even after having proper knowledge about this fact, you being the mayor, are not taking any charge of this situation.

The town is situated just by the side of River Ganges which makes it's soil full of moisture. Along with the repeated deforestation and tree cutting for urbanisation, the smallest of the rain falls are also eroding a lot of soils. This can lead to severe landslides in river Ganges with severe loss of properties as well as loss of lives too.

So i request you to start embanking the river as well as to start planting new trees to save the town from getting lost under Ganges.

Thanking you,

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5 0
2 years ago
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Polycystic ovary syndrome is an endocrine disorder and a common cause of chronic anovulation. In addition to the clinical manife
Scilla [17]

Answer:

1. Insulin resistance and diabetes

2. Metformin

Explanation:

Metformin can be used to treat polycystic ovary syndrome, especially for insulin-resistant women (insulin is a hormone that transports sugar into cells).

People with insulin resistance have high levels of this hormone in their blood and excess circulating insulin can aggravate manifestations of polycystic ovary syndrome, and also increase the risk of diabetes.

The main benefits of metformin in the treatment of polycystic ovaries is the normalization of menstrual irregularity and the restoration of ovulatory cycles.

Since most women with polycystic ovary syndrome are insulin resistant, metformin is a good treatment option in some cases.

However, the treatment of polycystic ovary syndrome should be individualized for each woman, depending on the symptoms presented and the goal to be achieved with the treatment.

8 0
2 years ago
The first visible signs of senescence are usually observed in a person's ___
DerKrebs [107]
Skin is the correct answer
6 0
2 years ago
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There are six people in the Fisher family. Olivia and Marcus are the parents. They have four children: Violet, Nathan, Jonas, an
Trava [24]
<span> Wow, this is a big question, but here goes. Freckles q: 1) Since freckles is the dominant phenotype, this means that Olivia must have the recessive phenotype, which is only given by the genotype ff. FF and Ff would both give freckles because, again, freckles is dominant. So any genotype with F_ would give freckles. 2)Same answer as #1. 3) Since they only have f alleles to pass on, both the dad and the mom will pass on one f each to 100% of their children. So all will have genotype ff and no freckles.
Hairline q: Since the parents are heterozygous, this means that their genotype has one of each allele to give Hh. (Even though you said they are quadruplets, I'm going to assume they are fraternal (different DNA) b/c otherwise they'd always have the same genotype if they are identical). 1) Okay, so when you do the Punnett square for Hh x Hh, you'll get 1HH:2Hh:1hh. Since widow's peak is dominant, any genotype with H_ gives the widow's peak. So, there are 3 options from the Punnett square, so you'll have 3 of the kids with widow's peak. Theres a 3/4 chance that a child will have widow's peak from these parents. 2) Since straight hairline is recessive, you need hh to get this phenotype and there is only one option. So, there will only be one child with the straight hairline. (1/4 chance). 3) Homozygous dominant means that you have two of the dominant allele, so HH. Since there is only 1 option, there is only one child with this genotype.
Tongue q: Since rolling the tongue is a dominant trait and the parents both can't roll their tongues, they must have a homozygous recessive genotype for this to happen (remember in dominance, any genotype with a dominant allele will give the dominant phenotype), so they have tt. 1) Since again they can only pass on t alleles, the kids will all have tt, so no one can roll their tongues. 2) None of them are hybrids because there was no variety in the genotypes or anything. Both parents had tt, so they were same in genotype. 3) She will have tt because of the above stated reasons.
Dimples q: Since all four kids have dimples, the dominant phenotype, they must all have the genotype D_ (either Dd or DD). 1) Since Marcus is a hybrid, this means that he had parents that were DD x dd to give him the genotype Dd. Since he has a recessive allele d in his genotype, Olivia must have all dominant alleles to make sure that each child has at least one dominant D. So, she must have the genotype DD. 2) Since she is DD, the dominant alleles will make her have dimples.
Earlobe q: 1) Since the parents are EE both, a cross of EE x EE will give EE genotype children. So, all children have EE, this means they all have free earlobes. So the ratio is 100% free to 0% attached earlobes. 2)Homozygous means they have two of the same alleles. Since all of them have EE, 100% of them are homozygous.
PTC q: Marcus has genotype bb and Olivia has genotype Bb because she is heterozygous. 1) The cross of bb x Bb gives 1Bb:1bb, So, 1/2 can taste the paper, so 50% can taste. 2) Since Violet can't taste the paper, she must be recessive and have the genotype bb. Since both of the boys can taste, they must have the genotypes Bb. Since 1/2 is already Bb, Claudia must be bb to help create the 50% that can't taste in the kids. 3)So, 2 people out of the family can taste the paper. Even though Olivia has Bb and should be able to taste, she can't. So, only Jonas and Nathan can taste the paper.
Pheww... done.. Hope this helps! :)<span>
</span></span>
7 0
2 years ago
Read 2 more answers
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