Question

Please help!! Ashley has x dollars she spends $23.50 on a new top she decides to keep 2 fifths of what she has left which is $13.80 how many dollars did Ashley have originally?

Answer 1

Answer:

Ashley has $58 initially

Step-by-step explanation:

Let Ashley has x dollars initially.

Dollars spent on new top = $23.50

Amount of money Ashley is left with :

$\frac{2}{5}\text{ of }13.80\\\\\implies \frac{2}{5}\times 13.80\\\\\implies Amount = \ 34.50$

So, Initial dollars Ashley has, x = Dollars spent + Dollars left

                                             ⇒ x  = 23.50 + 34.50

                                            ⇒ x  = $58

Hence, Ashley has $58 initially

Answer 2

Answer:

Ashley has $58 initially.

Step-by-step explanation:

Let $x be the initial amount Ashley has.

Dollars spent on new top = $23.50

Amount of money Ashley is left with : $(x - 23.50)

It is given that Ashley decides to keep 2 fifths of what she has left which is $13.80.

$\frac{2}{5}\times (x - 23.50)=13.80$

$0.4\times (x - 23.50)=13.80$

Using distribution property, we get

$0.4x - 0.4(23.50)=13.80$

$0.4x - 9.4=13.80$

Add 9.4 on both sides.

$0.4x=13.80+9.4$

$0.4x=23.2$

Divide both sides by 0.4.

$\frac{0.4x}{0.4}=\frac{23.2}{0.4}$

$x=58$

Therefore, the initial amount is $58.