Assuminhg the ark has a shoe-box (cuboid) shape it´s volume would be:
We have this three measurements (
) and it can be as simple as replacing them in the equation and solving but they are in all in 
. We will convert them to 
because the problem requires the answer in 
. In order to do this we will use the given equivalences:
and another one:
First we will convert from cubits to palms:
now from 
to 
:
now from to :
We can calculate the Volume now like this:
The volume of trhe ark would be 
Here we are given the specific equation of:
amount of eroded soil = 0.4 + 1.3 x
where x is the flow rate
A linear equation has a general formula in the form of:
y = m x + b
where m is the slope and b is the y intercept of the equation
If we compare this with our specific equation, we can see that the slope and y intercept are both positive with values:
m = 0.4
b = 1.3
Therefore this only means that as the flow rate increases, the amount of eroded soil also increases.
Hence the correlation must be positive but we cannot solve for the exact value since we need the data for x and y.
Answer:
positive, but we cannot say what the exact value is
Hello,
The median of the temperatures at Springwood is 86. (median is at the middle).
the median of the temperatures at Meadows is 73. (median is at the middle).
The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).
The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).
the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.
After the first three days, the sample size will be half of the initial; therefore, 400g/2= 200g. However, it is asking how long will it take to decay to 100g, so we will take 200g/2= 100g, which will take another three days. It will take 2 half-lives, which will encompass 6 days.
