Answer:
The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 1.1156 occur / millimeters
Step-by-step explanation:
<u>Step 1</u>:-
Given data A copper wire, it is known that, on the average, 1.5 flaws occur per millimeter.
by Poisson random variable given that λ = 1.5 flaws/millimeter
Poisson distribution 
<u>Step 2:</u>-
The probability that no flaws occur in a certain portion of wire

On simplification we get
P(x=0) = 0.223 flaws occur / millimeters
<u>Conclusion</u>:-
The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 5 X P(X=0) = 5X 0.223 = 1.1156 occur / millimeters
6x15= 90
9x20= 180
180+90= 270
270 - 25 = 245 dane has 245 stamps left
Answer:
4x + 6
Step-by-step explanation:
Given
+ 
Before we can add the fractions we require them to have a common denominator.
Factor the denominator of the first fraction
+ 
Multiply the numerator / denominator of the second fraction by (x + 2)
=
+
← fractions now have a common denominator
Add the numerators leaving the denominators
= 
= 
=
← simplified sum with numerator 4x + 6
Answer:
34 inches
Step-by-step explanation:
Area is base times height time half
Then plug in the values: 136= 0.5 x 8x
Then solve for x