We know the following relationship:

The
domain of a function are the
inputs of the function, that is, a function

is a relation that assigns to each element

in the
set A exactly one element in the
set B. The set A is the domain (or set of inputs) of the function and the set B contains the range (or set of outputs).Then applying this concept to our function

we can write its domain as follows:
1. D<span>
omain of validity for 
:
</span>
When:

?
when:
where k is an integer either positive or negative. That is:

To match this with the choices above, the answer is:
<span>
"All real numbers except multiples of
"
</span>
2. which identity is not used in the proof of the identity 
:
This identity can proved as follows:

The identity that is not used is as established in the statement above:
<span>
"1 +cos squared theta over sin squared theta= csc2theta"
Written in mathematical language as follows:
</span>

<span>
</span>
Answer:
10*10=100
50*2=100
5*20-100
Step-by-step explanation:
Answer:
The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Step-by-step explanation:
Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.
The random variable <em>X</em> is exponentially distributed with mean 7 minutes.
Then the parameter of the distribution is,
.
The probability density function of <em>X</em> is:

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

![=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148](https://tex.z-dn.net/?f=%3D%5Cint%5Climits%5E%7B9%7D_%7B6%7D%20%7B%5Cfrac%7B1%7D%7B7%7D%5Ccdot%20e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B7%7D%5Ccdot%20%5Cint%5Climits%5E%7B9%7D_%7B6%7D%20%7Be%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5B-e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%5D%5E%7B9%7D_%7B6%7D%5C%5C%5C%5C%3De%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%206%7D-e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%209%7D%5C%5C%5C%5C%3D0.424373-0.276453%5C%5C%5C%5C%3D0.14792%5C%5C%5C%5C%5Capprox%200.148)
Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Find the unit rate :
4 notebooks for 7 bucks.......7/4 = 1.75 per notebook
10 folders for 2.50....2.50/10 = 0.25 per folder
so 5 notebooks = 5(1.75) = 8.75
6 folders = 6(0.25) = 1.50
for a total of : (8.75 + 1.50) = 10.25 <==
Answer:
3 hours 20 minutes
Step-by-step explanation:
Together, the workers can assemble 9 + 6 = 15 products per hour. So the assembly of 50 products will take ...
(50 products)/(15 products/hour) = 50/15 hours = 3 1/3 hours
The two workers can assemble 50 products in 3 1/3 hours.