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Brums [2.3K]
2 years ago
4

Solve for X and Y 3x+(2 x-y)i = 6-3i

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
4 0

Answer:

<h2>x = 2 and y = 7</h2>

Step-by-step explanation:

\text{Two complex numbers are equal when they have equal real parts}\\\text{ and equal imaginary parts}\\\\a+bi=c+di\iff a=c\ and\ b=d

3x+(2x-y)i=6-3i\iff3x=6\ \wedge\ 2x-y=-3\\\\3x=6\qquad\text{divide both sides by 3}\\\\\boxed{x=2}\\\\\text{Put the value of x to the second equation:}\\\\2(2)-y=-3\\\\4-y=-3\qquad\text{subtract 4 from both sides}\\\\-y=-7\qquad\text{change the signs}\\\\\boxed{y=7}

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Sample space for two tosses of a coin [HH, TT, HT,TH]

Step-by-step explanation:

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2 years ago
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Question 1: Classify the system of equations and identify the number of solutions. 3 = 4x + y 2y = 6 − 8x Answers: inconsistent;
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Answer:

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Which rule describes the composition of transformations that maps ΔABC to ΔA"B"C"?
MaRussiya [10]

Answer:

<h2>Reflection across the<em> x-axis</em> composition translation of negative 6 units <em>x</em>, negative 2 units <em>y</em>.</h2>

Step-by-step explanation:

To find the right order in this transformations from ΔABC to ΔA"B"C", we first need to consider that the initial figure is ΔABC, which is transformed to  ΔA'B'C', and then to  ΔA''B''C''.

So, from the image we can see that from ΔABC to  ΔA'B'C', the transformation applied is reflection across the <em>x-axis</em>, because ΔA'B'C' is an inverted image of the original, like a mirror.

Then, from ΔA'B'C' to ΔA''B''C'', we can see that the transformation is a combination of translations, to the left side and down side. From the graph we can see that it moved exactly, 6 negative units in the direction of the <em>x-axis</em>, and 2 negative units in the direction of the <em>y- axis</em>, in other words, it moved 6 units to the left and 2 units down.

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<em>Reflection across the x-axis composition translation of negative 6 units x, negative 2 units y.</em>

<em></em>

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2 years ago
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Using P(M) ×P(N)= P(M and N)

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