5, 8, 11, ... is an arithmetic sequence where:
Answer:
After 15 years both the colleges will have same number of students.
Step-by-step explanation:
The enrollment at sunshine College has been increased by 45 students per year. Currently, sunshine College has 1100 students attending.
So, after x years the number of students of this college will be (1100 + 45x).
Again, Marigold college currently has 2000 students, but its enrollment is decreasing in size by an average of 15 students per year.
So, after x years the number of students of this college will be (2000 - 15x).
If those two colleges have the same number of students after x years, then we can write
1100 + 45x = 2000 - 15x
⇒ 60x = 900
⇒ x = 15 years.
Therefore, after 15 years both the colleges will have the same number of students. (Answer)
Yes; it is possible
<span>If the planes are parallel to each other then they don't intersect. </span>
<span>There can also be two or more lines on different planes which do not intersect each other. These lines are called skew lines.</span>
Let number of yellow marbles = x
Let number of red marbles = y
Let number of blue marbles = z
Given that Finley has 152 yellow, red, and blue marbles in a bag.
So we get equation:
x+y+z=152...(i)
"He has seven more red marbles than yellow marbles" means:
y=x+7...(ii)
"three times as many blue marbles as yellow marbles." means:
z=3x...(iii)
Now we just need to solve those equations to find the answer.
Plug (ii) and (iii) into (i)
x+(x+7)+(3x)=152
x+x+7+3x=152
Which looks similar to choice (B)
5x+7=152
5x=145
x=29
Hence final answer is choice B.
Required equation is
x+x+7+3x=152
Number of yellow marbles = 29
Add all the new budget amounts:
510 + 254 + 295 + 51 + 0 + 100 + 100+ 0 + 100 = 1410
Her monthly total is 1410, which is less than her income of 1700
1700 - 1410 = 290
She has $290 extra each month.
So she can divide that amount by 2 to put an equal amount in each blank category, or add what ever amount less than that into each one.
