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Sphinxa [80]
2 years ago
6

A pyramid is placed inside a prism as shown. The pyramid has the same base area, B, as the prism but half the height, h, of the

prism. Which expression gives the volume of the pyramid?
V = 2/3bh
V = 1/4bh
V = 2bh
V = 1/6bh
Mathematics
1 answer:
Alona [7]2 years ago
4 0
The general formula of a pyramid with any base is 1/3 bh where b is the area of the base and h is the height. In this case, the height of the pyramid is said to be twice the height of the prism, h. Hence the area becomes 1/3 b*2h or equal to option A. 2/3 bh
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Vlada [557]

Answer:

0.75 feet per second.

Step-by-step explanation:

Please find the attachment.

We have been given that a 25-ft ladder is leaning against a wall. We can see from the attachment that ladder forms a right triangle with respect to wall and ground.

So we can set a Pythagoras theorem as:

x^2+y^2=25^2

x^2+y^2=625

Now, we need to find the derivative of above equation with respect to time.

2x\cdot \frac{dx}{dt}+2y\cdot \frac{dy}{dt}=0

Since the adder is moving toward the wall at a rate of 1 ft/sec for 5 sec, so x after 5 seconds would be: 20-1(5)=20-5=15

Let us solve for y using Pythagoras theorem.

y^2+15^2=25^2

y^2+225=625

y^2=625-225

y^2=400

Take positive square root:

\sqrt{y^2}=\sqrt{400}

y=20

Upon substituting our given values in derivative equation, we will get:

2x\cdot \frac{dx}{dt}+2y\cdot \frac{dy}{dt}=0

2(15)\cdot(-1)+2(20)\cdot \frac{dy}{dt}=0

-30+40\cdot \frac{dy}{dt}=0

40\cdot \frac{dy}{dt}=30

\frac{dy}{dt}=\frac{30}{40}

\frac{dy}{dt}=0.75

Therefore, the ladder is moving up at a rate of 0.75 feet per second.

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Step-by-step explanation:

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