Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
Answer:
Explanation:
The clients that would be best suited for this opportunity would be small business or business' that do not have the hardware/space resources necessary to create the computing power that they need. Instead, they can simply pay for these cloud-based services which provide all of the necessary computing/hardware power and resources necessary so that the company can easily fulfill all of their tasks without any problems. Bigger companies can easily pay for and implement their own hardware to solve their problems which may benefit them even more in the long-term.
Telecommunications is the electronic transmission of signals for communications, which enables organizations to carry out their processes and tasks through effective computer networks
total = 0
for x in range(99, 0, -1):
total += x
print(total)
I hope this helps!
Answer:
10 20
30 40
50 60
Explanation:
Given
The above code segment
Required
What is printed, if anything
To do this, we analyze the code line by line.
Line 1: The first line creates a 4 by 3 array named mat
Line 2: for (int[] row : mat)
{ -> This creates row[] array which represents each row of array mat
Line 3: for (int j = 0; j < row.length; j += 2){ -> This iterates through the even indexed elements of the row array i.e. 0 and 2
Line 4: System.out.print(row[i] + " "); -> This prints the even indexed elements of the row array.
The even indexed elements are: 10, 20, 30, 40, 50 and 60
Line 5: System.out.println();
--> This prints a new line
