Answer:
Ctrl+Space is the keyboard shortcut to select an entire column.
Explanation:
When you press the Shift+Space shortcut the first time it will select the entire row within the Table. Press Shift+Space a second time and it will select the entire row in the worksheet.
The same works for columns. Ctrl+Space will select the column of data in the Table. Pressing the keyboard shortcut a second time will include the column header of the Table in the selection. Pressing Ctrl+Space a third time will select the entire column in the worksheet.
You can select multiple rows or columns by holding Shift and pressing the Arrow Keys multiple times.
Answer:
Let's convert the decimals into signed 8-bit binary numbers.
As we need to find the 8-bit magnitude, so write the powers at each bit.
<u>Sign -bit</u> <u>64</u> <u>32</u> <u>16</u> <u>8</u> <u>4</u> <u>2</u> <u>1</u>
+25 - 0 0 0 1 1 0 0 1
+120- 0 1 1 1 1 0 0 0
+82 - 0 1 0 1 0 0 1 0
-42 - 1 0 1 0 1 0 1 0
-111 - 1 1 1 0 1 1 1 1
One’s Complements:
+25 (00011001) – 11100110
+120(01111000) - 10000111
+82(01010010) - 10101101
-42(10101010) - 01010101
-111(11101111)- 00010000
Two’s Complements:
+25 (00011001) – 11100110+1 = 11100111
+120(01111000) – 10000111+1 = 10001000
+82(01010010) – 10101101+1= 10101110
-42(10101010) – 01010101+1= 01010110
-111(11101111)- 00010000+1= 00010001
Explanation:
To find the 8-bit signed magnitude follow this process:
For +120
- put 0 at Sign-bit as there is plus sign before 120.
- Put 1 at the largest power of 2 near to 120 and less than 120, so put 1 at 64.
- Subtract 64 from 120, i.e. 120-64 = 56.
- Then put 1 at 32, as it is the nearest power of 2 of 56. Then 56-32=24.
- Then put 1 at 16 and 24-16 = 8.
- Now put 1 at 8. 8-8 = 0, so put 0 at all rest places.
To find one’s complement of a number 00011001, find 11111111 – 00011001 or put 0 in place each 1 and 1 in place of each 0., i.e., 11100110.
Now to find Two’s complement of a number, just do binary addition of the number with 1.
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Answer:
I will code in JAVA.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
boolean tallEnough;
boolean oldEnough;
Scanner input = new Scanner(System.in);
tallEnough = input.nextBoolean();<em> //wait the input for tallEnough</em>
oldEnough = input.nextBoolean(); <em>//wait the input for OldEnough</em>
if(tallEnough && oldEnough){
System.out.print(true);
} else {
System.out.print(false);
}
}
}
Explanation:
First, to accept user inputs you have to import the class Scanner. Then declare both variables before allowing the user to set input values for both boolean variables.
In the if-else statement checks if both variables are true, then prints true. Another case prints always false.
Answer:
Explanation:
import java.util.Scanner;
public class KboatTriangleAngle
{
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
System.out.print("Enter first angle: ");
int a1 = in.nextInt();
System.out.print("Enter second angle: ");
int a2 = in.nextInt();
System.out.print("Enter third angle: ");
int a3 = in.nextInt();
int angleSum = a1 + a2 + a3;
if (angleSum == 180 && a1 > 0 && a2 > 0 && a3 > 0) {
if (a1 < 90 && a2 < 90 && a3 < 90) {
System.out.println("Acute-angled Triangle");
}
else if (a1 == 90 || a2 == 90 || a3 == 90) {
System.out.println("Right-angled Triangle");
}
else {
System.out.println("Obtuse-angled Triangle");
}
}
else {
System.out.println("Triangle not possible");
}
}
}
OUTPUT:
