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storchak [24]
2 years ago
12

Problem 5-35: Two genes control color in corn snakes as follows: O- B- snakes are brown, O- bb are orange, oo B- are black, and

oo bb are albino. An orange snake was mated to a black snake, and a large number of F1 progeny were obtained, all of which were brown. When the F1 snakes were mated to one another, they produced 100 brown offspring, 25 orange, 22 black, and 13 albino. a. What are the genotypes of the F1 snakes? (1 point) b. What proportions of the different colors would have been expected among the F2 snakes if the two loci assort independently? (1 point) c. Do the observed results differ significantly from what was expected, assuming independent assortment is occurring? What is the probability that differences this great between observed and expected values would happen by chance? (3 points)
Biology
1 answer:
Svetach [21]2 years ago
7 0
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You are invited to participate in a debate about the concept of evolution. Construct an opening statement supporting evolution,
Masja [62]

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7 0
2 years ago
A mutation in a gene in the fruit fly Drosophila was found to affect eye color. The protein affected was found to be completely
lilavasa [31]

Answer:

The correct option is D. A reasonable explanation for the change in levels of protein is that the mutation occurs in the promoter of the gene, within several hundred base pairs of the start of transcription.

Explanation:

In genetics, a promoter can be described as a region where the RNA polymerase binds initially and starts transcription. The promoter is usually present near to the gene that has to be transcribed. The rate of transcription is controlled by the promoter region too. Hence, the correct option is D. The promoter region for the eye colour was changed due to mutation.

Other options are false because a change in a codon or base pair would have changed proteins being formed and would not have slowed the process.

5 0
2 years ago
What is the correct complimentary strand for the following DNA?ATCGAG
Mazyrski [523]
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5 0
2 years ago
To measure the population of lake trout in a 250-hectare lake, 400 individual trout were netted and marked with a fin clip, then
kenny6666 [7]

Answer:

Estimated size is 1600

Explanation:

Given data:

Size of lake is 250 hectares

Total number of trout who netted is 400

Total number of trout in next week is 200

Total number of trout having fin clip 50

estimation population size is estimated by mark rupture as follow

Estimated population size = \frac{(marked\ initally \times total\ recaptured)}{mark\ recaptured}

Estimated size= \frac{400\times 200)}{50}

Estimated size is 1600

4 0
2 years ago
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