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Leya [2.2K]
1 year ago
12

Write a complete two-column proof for the following information. Hint: Use the Angle Addition Theorem and the fact that a line i

s made up of two opposite rays.
Given: m∠1 = 62° and lines t and l intersect
Prove: m∠4 = 62°

needs to be a actual two column proof with statements and reasons. im just not really understanding it

Mathematics
2 answers:
kramer1 year ago
6 0

Answer:

Step-by-step explanation:

Given: m∠1 = 62° and lines t and l intersect

Prove: m∠4 = 62°

Proof:

Statement                                        Reason

m∠1 = 62°                                         Given

m∠1 , m∠2 are supplementary       t is a straight line hence linear pair.

m∠4 , m∠2 are supplementary       r is a straight line hence linear pair.

Angle 2=180-62 = 118                      Definition of supplementary angles

Angle 4 = 180-118 =62                     -do-

Angle 1 = Angle 4                            Equality property

Hence proved

Brums [2.3K]1 year ago
4 0

Answer:

m∠1 = 62°                                         Given

m∠1 , m∠2 are supplementary       t is a straight line hence linear pair.

m∠4 , m∠2 are supplementary       r is a straight line hence linear pair.

Angle 2=180-62 = 118                      Definition of supplementary angles

Angle 4 = 180-118 =62                     -do-

Angle 1 = Angle 4                            Equality property

Step-by-step explanation:

Listed in the above answer!

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Colin gets pic 'n mix when at the cinema and makes his bag up with 3 types of sweet. He pick:
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4 0
1 year ago
For the binomial expansion of (x + y)^10, the value of k in the term 210x 6y k is a) 6 b) 4 c) 5 d) 7
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Answer:

a) 6

Step-by-step explanation:

Expanding the polynomial using the formula:

$(x+y)^n=\sum_{k=0}^n \binom{n}{k} x^{n-k} y^k $

Also

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

I think you mean 210x^6y^4

We can deduce that this term will be located somewhere in the middle. So I will calculate k= 5; k=6 \text{ and } k =7.

For k=5

$\binom{10}{5} (y)^{10-5} (x)^{5}=\frac{10!}{(10-5)! 5!}(y)^{5} (x)^{5}= \frac{10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5! }{5! \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 } \\ =\frac{30240}{120} =252 x^{5} y^{5}$

Note that we actually don't need to do all this process. There's no necessity to calculate the binomial, just x^{n-k} y^k

For k=6

$\binom{10}{6} \left(y\right)^{10-6} \left(x\right)^{6}=\frac{10!}{(10-6)! 6!}\left(y\right)^{4} \left(x\right)^{6}=210 x^{6} y^{4}$

5 0
2 years ago
6 points Emily’s family needs to rent a moving truck to move their belongings to a different house. The rental cost for Trucks-A
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Answer/Step-by-step explanation:

Equation to represent the daily rental cost for each type of truck can be written as follows:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Where, m = Emily's mileage

To determine the number of miles for which the truck cost the same amount, set both equations equal to each other and solve for m.

42 + 0.72m = 70 + 0.12m

Collect like terms

0.72m - 0.12m = 70 - 42

0.6m = 28

Divide both sides by 0.6

\frac{0.6m}{0.6} = \frac{28}{0.6}

m = 46.7

At approximately 47 miles, both trucks would cost the same amount.

Check:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Plug in the value of x = 47

= 42 + 0.72(47) = $75.84 ≈ $76

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Plug in the value of x = 47

= 70 + 0.12(47) = $75.64 ≈ $76

7 0
2 years ago
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