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Sonja [21]
2 years ago
3

If a computer depreciates at a rate of 24% per year, what is the monthly depreciation rate?

Mathematics
1 answer:
yanalaym [24]2 years ago
8 0

The answer would be 2. 00%. One year has 12 months included. Therefore, unless it depreciates unequally throughout the year, the equation would be 24%÷12. And the answer would so be 2. 00%

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Write tge slope-Intercept form of the equation of each line given the slooe a and y-Intercept.
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y= -1/2x-3

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I hope that this helps

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The radar on a ship picks up two shipwrecks, A and B, 2.5 miles beneath the surface. The distance between the shipwrecks is 0.6
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A parallelogram has a base of 10 centimeters and a height of 4 centimeters. What is the area of the parallelogram?
Illusion [34]

Step-by-step explanation:

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One evening 1400 concert tickets were sold for the Fairmont Summer Jazz Festival. Tickets cost ​$20 for covered pavilion seats a
Sidana [21]
The answer to the question

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2 years ago
the jellybean jar has a radius of 4.8 cm and a height of 11.8 cm. what would be a reasonable lower limit for the number of jelly
azamat

Answer:

           \large\boxed{\large\boxed{100}}

Explanation:

This question comes with four answer choices:

  • 10,000
  • 100,000
  • 100
  • 1

You just need to find a rough estimate of the volume of the jar and the volume of one jelly bean. This is called magnitude order.

The <em>jellybean ja</em>r is cylindrical, Thus, its volume is \pi \times radius^2\times height

To find the order of magnitude, you just use the numbers rounded to one signficant figure: round π to 3, the radius to 5, cm, and the height to 10:

            Volume\approx 3cm\times (5cm)^2\times10cm=750cm^3\approx1,000cm^3

The order of magnitude for the radius of a jellybean is 1 cm. And the order of magnitude of the volume of a sphere with a radius of 1 cm is the cube of the diameter (2cm):

             (2cm)^3=8cm^3\approx10cm^3

Hence, a reasonable lower limit for the number of jellybeans in the jar is:

                     1,000cm^3/10cm^3=100

7 0
2 years ago
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