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kirill115 [55]
2 years ago
15

What are the end points of the triangle called? How are they labeled?

Mathematics
1 answer:
horrorfan [7]2 years ago
6 0

For this case we have that by definition:

A triangle is defined by three lines that are called sides, or by three points called vertices.

We know that:

  1. <em>The vertices of a triangle are labeled with capital letters. </em>
  2. <em>The sides of a triangle are written with lowercase letters. </em>
  3. <em>The angles of a triangle are written similarly to the vertices. </em>

Answer:

The end points of the triangle are called vertices.

They are labeled in capital letters.

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We will evaluate both expressions step by step.

 Sylvia's espression:
 h + 0.05h
 h: Original hat price.
 0.05h: Increase of 5% due to sales tax.

 Jin's expressions:
 1.05h 
 h: Original hat price.
 1.05: Factor for which you must multiply the original price to add 5% due to sales tax.
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According to the Rational Root Theorem, Negative two-fifths is a potential rational root of which function?
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Answer:

f(x) = 4x4 – 7x2 + x + 25 f(x) = 9x4

Step-by-step explanation:

Because it has to be this one

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Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap
strojnjashka [21]

Answer:

The value of the parameter is λ is 0.03692

Step-by-step explanation:

Consider the provided function.

f(x) = 0.5\lambda e^{-\lambda |x|} for −∞ < x < ∞.

It is given that standard deviation is given as 38.3 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

\lambda=\frac{1}{\beta} and μ = 0.

Standard deviation = √2β

S.D=\sqrt{2} \beta\\\beta=\frac{38.3}{\sqrt{2}}\\\beta=27.08219

Now substitute the value of β in \lambda=\frac{1}{\beta}.

\lambda=\frac{1}{27.08219}=0.03692

Hence, the value of the parameter is λ is 0.03692

7 0
2 years ago
In circle A shown, BC || DE , mBC=58° and mDE=142°. Determine the measure of ZCFE . Show how you arrived at your answer.
AysviL [449]

Answer:

< CFE = 40°

Step-by-step explanation:

To better understand the solution, see attachment for the diagram.

Given:

BC parallel to DE

Measure of Arc BD = 58°

Measure of Arc DE = 142°

First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.

The line ST divides the arc BD and arc DE into half.

That is:

Arc SC = 1/2(arc BC) =1/2(58)

Arc SC = 29°

Arc TE = 1/2(arc DE) =1/2(142)

Arc TE = 71°

Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle

29° + Arc CE  + 71° = 180°

Arc CE + 100° = 180°

Arc CE = 180-100

Arc CE = 80°

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5 0
2 years ago
Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the followin
svp [43]

Answer:

a) 1+2+3+4+...+396+397+398+399=79800

b) 1+2+3+4+...+546+547+548+549=150975

c) 2+4+6+8+...+72+74+76+78=1560

Step-by-step explanation:

We know that a summation formula for the first n natural numbers:

1+2+3+...+(n-2)+(n-1)+n=\frac{n(n+1)}{2}

We use the formula, we get

a) 1+2+3+4+...+396+397+398+399=\frac{399·(399+1)}{2}=\frac{399· 400}{2}=399· 200=79800

b) 1+2+3+4+...+546+547+548+549=\frac{549·(549+1)}{2}=\frac{549· 550}{2}=549· 275=150975

c)2+4+6+8+...+72+74+76+78=S / ( :2)

1+2+3+4+...+36+37+38+39=S/2

\frac{39·(39+1)}{2}=S/2

\frac{39·40}{2}=S/2

39·40=S

1560=S

Therefore, we get

2+4+6+8+...+72+74+76+78=1560

5 0
2 years ago
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