What values of b satisfy 3(2b+3)^2 = 36
we have
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
take the square root of both sides
( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3
b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}
b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
therefore
the answer is
the values of b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
<em>Greetings from Brasil...</em>
According to the question of the statement, we can conclude that
PQ = 2B
QR = 2B
PR = base = B
Perimeter = P = 105
P = PQ + QR + PR
105 = 2B + 2B + B
B = 21
<h2>PQ = 2B = 42</h2><h2>QR = 2B = 42</h2>
The answer is B
a1= 13;an-1+2
3 is incorrect because 14.7 + 3 = 17.7
The answer of 15 - 14.7 = 0.3
Answer:
166
Step-by-step explanation:
$15.00-$5.00= $10.00 (subtract five dollars because aiden wants to have at least five dollars left)
10.00 divided by 0.06= 166
I hope this helps! :)
