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patriot [66]
1 year ago
5

Cos (pi/2-x) = sin x true or false?

Mathematics
2 answers:
shepuryov [24]1 year ago
7 0

this would be True hoped i helped

Annette [7]1 year ago
5 0

Answer: The answer is I fact TRUE

Step-by-step explanation:

I know this because of ap*x

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Peter's salary is twice Anne's salary and half of David's salary. Then the average salary of Anne and David is _ of Peter's sala
satela [25.4K]
<h3><u>Answer:</u></h3>

Average of salary of Anne and David is 1.25 of Peter's Salary

<h3><u>Explanation:</u></h3>

In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.

Let us assume Peter's Salary as P.

Then we can calculate Anne's salary A = \frac{P}{2}.

Also David's salary = D = 2 \times P

Average of Anne's and David's salary = \frac{A+D}{2}

Average of Anne's and David's salary  = \frac{\frac{P}{2} + 2 \times P}{2}

Average of Anne's and David's salary  = \frac{5 \times P}{4}

Average = 1.25 \times P

6 0
1 year ago
One of your employees has suggested that your company develop a new product. You decide to take a random sample of your customer
iren [92.7K]

Answer:

269

Step-by-step explanation:

The margin of Error is E = 0.05

The level of significance is, α = 1 - confidence level = 1 - 0.9 = 0.1

Assume that the proportion is, p =0.5

From the standard normal table, observe that the critical value of Z for two tail test and 10% level of significance is 1.64

The calculation of sample size is as follows: n = (Z/E)²p(1-p)

n = (1.64/0.05)²0.5 (1 - 0.5)

n = (1.64/0.05)² 0.25

n = 1075.84 × 0.25

n = 268.96 ≈ 269

The required sample size with the given margin of error approximately is 269. This value indicates the size of the customers who are using this company’s products.

6 0
2 years ago
Theresa rolled a number cube, number 1 through 6, two times
muminat

Answer:

B

Step-by-step explanation:

8 0
1 year ago
Read 2 more answers
Martin had 7 pounds of grapes left, and he gave away 2 5 of them. Explain how to use compatible numbers to estimate the amount o
nalin [4]

Compatible numbers are numbers which are easy to do mental calculation. For example is when doing division like 25 and 5, 100 and 10, and 36 and 6.

First, we know that: 7 pounds=5 pounds + 2 pounds

                                or 7=5+2

In mathematics, the word “of” means to multiply. So:

                                grapes given away = 7  * (2/5)

Replacing 7 with 5 and 2:

                                                                = (5+2)*(2/5)

Using the distribution principle:

                                                =5*(2/5) + 2*(2/5)

                                                =2+ 4/5

                                =2 4/5

So grapes given away is 2 4/5 pounds.

3 0
2 years ago
Read 2 more answers
Calculate the standard deviation of the distribution of sample means. Write you answer in terms of fluid ounces and round to thr
NikAS [45]

Answer:

\sigma_{\bar X} =\frac{0.8}{\sqrt{8}}=0.283

Step-by-step explanation:

Assuming this question : "A bottling plant fills one-gallon jugs with milk. The labels on the jugs state that the volume of milk they contain is 128 fluid ounces (fl. oz.). Federal law mandates that the jugs must contain no less than the stated volume. The actual volume of milk in the jugs is normally distributed with mean μ=129 fl. oz. and standard deviation σ=0.8 fl. oz. Plant workers take a simple random sample (SRS) of 8 jugs, measure the volume of milk in each jug, and calculate the sample mean".

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the volume of milk in the jugs of a population, and for this case we know the distribution for X is given by:

X \sim N(129,0.8)  

Where \mu=129 and \sigma=0.8

Since the distribution for X is normal then the distribution for the sample mean  is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sample mean would be given by:

\sigma_{\bar X} =\frac{0.8}{\sqrt{8}}=0.283

6 0
2 years ago
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