Question

What is the solution of log2 (3x - 7) = 3?

Answer 1

To solve this question, all you have to do is take 2 raise it to 3, and make it equal to the expression 3x-7 and solve for x.
2^3=3x-7
8=3x-7
8+7=3x
15=3x
15/3=3x/3
5=x.
X=5.
You can verify if the answer is correct by plugging the value of 5 back into the original logarithmic equation.

Answer 2

Answer:

x = 5 is the solution of $\log _2 (3x-7) = 3$

Explanation:

Given that: $\log _2 (3x-7) = 3$

Using logarithmic properties:

if $\log_a x = b$

then;

$x = b^a$

Apply this rule on the given equation:

$(3x-7) = 2^3$

⇒$3x-7= 8$

Add 7 to both sides we get;

$3x= 15$

Divide both sides  by 3 we get;

x = 5

therefore,  the solution of $\log _2 (3x-7) = 3$ is 5