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Nesterboy [21]
2 years ago
14

What is the probability that a person who is above 35 years old has a hemoglobin level of 9 or above?

Mathematics
2 answers:
lorasvet [3.4K]2 years ago
4 0

Answer:

Option C. P=0.531

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space  (total person's hemoglobin level of 9 or above with age above 35 years)

y-----> size of the sample space  (total person's age above 35 years)

so

P=\frac{x}{y}

In this problem we have

y=162

Complete the table to find the total person's hemoglobin level of 9 or above (person's age above 35)

Let

y------> total person's hemoglobin level between 9 and 11 (person's age above 35)

y+76+40=162

y=46

Find the value of x

x=46+40=86

substitute the values

P=\frac{86}{162}=0.531

earnstyle [38]2 years ago
3 0

Answer:

The answer is C. 0.531

Step-by-step explanation:

Because

76+x+40= 162.

x= 162-76-40

x= 46

Hence,

40+46=86.

Therefore, probability that a person who is above 35 years old has a hemoglobin level of 9 or above is,

86/162= 0.531.

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A researcher took a random sample of 100 students from a large university. She computed a 95% confidence interval to estimate th
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Answer:

Part (A): The correct option is true.

Part (B): The null and alternative hypothesis should be:

H_o: \mu =0 ; H_a:\mu \neq0

Step-by-step explanation:

Consider the provided information.

Part (A)

A random sample of 100 students from a large university.

Increasing the sample size decreases the confidence intervals, as it increases the standard error.

If the researcher increase the sample size to 150 which is greater than 100 that will decrease the confidence intervals or the researcher could produce a narrower confidence interval.

Hence, the correct option is true.

Part (B)

The researcher wants to identify that whether there is any significant difference between the measurement of the blood pressure.

Therefore, the null and alternative hypothesis should be:

H_o: \mu =0 ; H_a:\mu \neq0

7 0
2 years ago
The R.R. Bowker Company of New York collects data on annual subscription rates to periodicals. Results are published in Library
Igoryamba

Answer:

90%

Step-by-step explanation:

Let's call the percentage of students that read Time magazine by P(T), and the percentage of students that read U.S News and World Report by P(U). So, we have that:

P(T) = 0.63

P(U) = 0.51

P(T and U) = 0.24

To find the percentage of students that read either the Time magazine or the U.S.News and World Report magazine (that is, P(T or U)), we can use this formula:

P(T or U) = P(T) + P(U) - P(T and U)

So, we have that:

P(T or U) = 0.63 + 0.51 - 0.24 = 0.90

So the probability is 90%

6 0
2 years ago
Find x if a= 13 and c= 47
Leviafan [203]
Okay so you need to use the Pythagorean theorem which is a^2 + b^2 = c^2

13^2 + b^2 = 47

169 + b^2 = 2,209
Move constant to the right


b^2 = 2,209 - 169
Subtract the numbers

b^2 = 2,040
Take the root of both sides


The final steps an answers are above on the image;)


6 0
2 years ago
Tia made a scale drawing of the White House for her history project. The actual length of the building is 168 feet, and its widt
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The answer is 1 inch to 9 feet
4 0
2 years ago
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Felipe planted some seeds for a science project. One of his plants grew 6 2/7 inches in the first week, and then it grew 5 11/14
MatroZZZ [7]

Answer:

<em>The plant grew </em>12\frac{1}{14}<em> inches</em>

Step-by-step explanation:

<u>Operations with Fractions</u>

Felipe planted seeds for a science project. One of the plants grew 6 2/7 inches in the first week and 5 11/14 inches in the second week.

We are required to find the total growth during the two weeks. We have to find the sum of:

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Let's convert both fractions to improper form:

6\frac{2}{7}+5\frac{11}{14}=6+\frac{2}{7}+5+\frac{11}{14}

Adding the integers:

6\frac{2}{7}+5\frac{11}{14}=11+\frac{2}{7}+\frac{11}{14}

Now we find the LCM of 7 and 14 is 14, thus:

6\frac{2}{7}+5\frac{11}{14}=11+\frac{4}{14}+\frac{11}{14}

6\frac{2}{7}+5\frac{11}{14}=11+\frac{15}{14}=11+\frac{14+1}{14}

6\frac{2}{7}+5\frac{11}{14}=11+1+\frac{1}{14}

6\frac{2}{7}+5\frac{11}{14}=12+\frac{1}{14}

Rewriting as a mixed number:

The plant grew 12\frac{1}{14} inches

8 0
2 years ago
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