Colin spends 3 4 of his wages on rent and 1 8 on food. If he makes £464 per week, how much money does he have left

Marcus baked a loaf of banana bread fora party . He cut the loaf into equal size pieces . At end of the party , there were 6 pie

Inessa05 [86]

8 Is total of a whole piece of a whole. So 3 were token from the whole.

6 0

2 years ago

Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.

olya-2409 [2.1K]

Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(

7 0

2 years ago

Read 2 more answers

Drag each expression to show whether it is equivalent to

Kazeer [188]

Answer:

We need to find which expressions are equivalent to $6(c+6)$ , $6c+6$ or neither.

$6c+12$ : We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.

$6c+12=+(c+2)$

Therefore, this expression is equivalent to neither of the given expressions.

$2(3c+3)$ : We just need to apply the distributive property.

$2(3c+3)=6c+6$

Therefore, this expression is equivalen to $6c+6$ .

We use the same process to the other expressions.

$(6c)+(6\times 6)=6c+36=6(c+6)$

$3c+6+3c=6c+6$

$6c+36=6(c+6)$

$(6+c)+(6+6)=c+18$ , equivalent to neither.

7 0

2 years ago

The position of an open-water swimmer is shown in the graph. The shortest route to the shoreline is one that is perpendicular to

Elenna [48]

Answer:

$y = -\frac{4}{3}x + 9$

Step-by-sep explanation:

To create an equation that represents the shortest oath of the swimmer that is perpendicular to the shoreline, we need to find the slope, m, and the y-intercept, b.

The slope of the path would be the negative reciprocal of the slope of the shoreline, since they are perpendicular.

Let's find the slope of the shoreline.

Using two points on the shoreline, (0, 1) and (4, 4),

Slope (m) = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - 1}{4 - 0} = \frac{3}{4}$

Therefore the slope, m, of the swimmer's path that is perpendicular to the shoreline would be -⁴/3.

Use the point of the swimmer and the slope of the path to find b.

Substitute m = -⁴/3, (x, y) = (6, 1) in $y = mx + b$

$1 = (-\frac{4}{3})(6) + b$

$1 = -8 + b$

Add 8 to both sides

$1 + 8 = b$

$9 = b$

$b = 9$

Now that we know the slope, m = -⁴/3, and the y-intercept, b = 9, plug in their values into $y = mx + b$ .

The equation of the path would be:

$y = -\frac{4}{3}x + 9$

5 0

2 years ago

The following histogram presents the amounts of silver (in parts per million) found in a sample of rocks. One rectangle from the

gladu [14]

Answer:

The height of the missing rectangle is 0.15

Explanation:

The image attached has the mentioned histogram.

Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.

Only the rectangle for the class [3,4] is missing.

The height of each rectangle is the relative frequency of the corresponding class.

The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.

In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.

1. Sum of the known relative frequencies:

0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85

2. Missing frequency:

1 - 0.85 = 0.15

3. Conclusion:

The height of the missing rectangle is 0.15

4 0

2 years ago