<em>Greetings from Brasil...</em>
According to the question of the statement, we can conclude that
PQ = 2B
QR = 2B
PR = base = B
Perimeter = P = 105
P = PQ + QR + PR
105 = 2B + 2B + B
B = 21
<h2>PQ = 2B = 42</h2><h2>QR = 2B = 42</h2>
Let us say that the number is x.
So the first step that Julio do is to cube the number so
that:
x^3
Then the next he did was take cube root of the number, so
that:
(x^3)^(1/3)
Solving this would result in:
x^(3/3) = x^1 = x
Since he ends up with 20, therefore:
x = 20
<span>Julio started and ended with the same number which is 20.</span>
Find the volume of a cone with a diameter of 20m and a slant height of 26m.
Volume Formula of a Cone: V = pi(radius^2)(h/3)
Diameter: 20m
Slant Height (Height): 26m
Plug it in:
V = 3.14(10^2)(26/3)
V = 314(26/3)
Solve:
V = 314(0.87)
V = 273.18
Volume = 273.18
Round:
Volume = 273m^3
The volume of the cone is 273m^3 to the nearest whole number.
Answer:
r(t) and s(t) are parallel.
Step-by-step explanation:
Given that :
the lines represented by the vector equations are:
r(t)=⟨1−t,3+2t,−3t⟩
s(t)=⟨2t,−3−4t,3+6t⟩
The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.
NOTE:
Two lines will be parallel if 
here;

Thus;



∴

Hence, we can conclude that r(t) and s(t) are parallel.
The question in English
At the Simón Bolívar educational institution, students in the second grade wish to represent on a 1:10 scale cardboard the rectangular-shaped blackboard of their classroom, which measures 3m base and 2m height.
WHAT WILL BE THE MEASUREMENTS OF THE GRAPH THEY REPRESENTED ON THE CARDBOARD?
Answer:

Step-by-step explanation:
we know that
The scale is equal to 
That means
unit on the cardboard is equal to
units on the actual
<u>Find the measurement of the base on the cardboard</u>
by proportion

<u>Find the measurement of the height on the cardboard</u>
by proportion

The measurements of the graph are
