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Keith_Richards [23]
2 years ago
3

It can be helpful to classify a differential equation, so that we can predict the techniques that might help us to find a functi

on which solves the equation. Two classifications are the order of the equation -- (what is the highest number of derivatives involved) and whether or not the equation is linear .
Linearity is important because the structure of the the family of solutions to a linear equation is fairly simple. Linear equations can usually be solved completely and explicitly. Determine whether or not each equation is linear:
1. (1+y2)(d2y/dt2)+t(dy/dt)+y=et

2. t2(d2y/dt2)+t(dy/dt)+2y=sin t

3. (d3y/dt3)+t(dy/dt)+(cos2(t))y=t3

4. y''-y+y2=0

You have 10 choices to choose for each problem:

a. 1st. order linear differential equation

b. 2nd. order linear differential equation

c. 3rd. order linear differential equation

d. 4th. order linear differential equation

e. 5th. order linear differential equation

f. 1st. order non-linear differential equation

g. 2nd. order non-linear differential equation

h. 3rd. order non-linear differential equation

i. 4th. order non-linear differential equation

f. 5th. order non-linear differential equation
Mathematics
1 answer:
IRINA_888 [86]2 years ago
5 0
Answer:

1. g. 2nd. order non-linear differential equation

2. a. 1st. order linear differential equation

3. c. 3rd. order linear differential equation

4. g. 2nd. order non-linear differential equation

Step-by-step explanation:

QUESTION 1

(1+y^2)(\frac{d^2y}{dt^2})+t\frac{dy}{dt} +y=e^t

Order: The highest derivative present in this differential equation is the second derivative (\frac{d^2y}{dt^2}). Hence the order of this differential equation is 2.

Linearity: There is the presence of the product of the dependent variable , y and its derivative [(1+y^2)(\frac{d^2y}{dt^2})].  

Hence this differential equation is non-linear.

Classification: Second order non-linear ordinary differential equation.

QUESTION 2

The given differential equation is  

t^2\frac{d^2y}{dt^2}+t\frac{dy}{dt} +2y=\sin t

Order: The highest derivative present in this differential equation is \frac{d^2y}{dt^2}

Hence it is a second order differential equation.

Linearity: There is no presence of the product of the dependent variable and/or its derivative. There is no presence of higher powers of the dependent variable or its derivative. There is no transcendental function of the dependent variable.

Classification: First order linear differential equation

QUESTION 3

The given differential equation is

\frac{d^3y}{dt^3}+t\frac{dy}{dx} +\cos (2t)y=t^3

Order: The highest derivative present in this differential equation is \frac{d^3y}{dt^3}

Hence it is a third order differential equation.

Linearity: There is no presence of the product of the dependent variable and/or its derivative. There is no presence of higher powers of the dependent variable or its derivative. There is no transcendental function of the dependent variable.

Classification: Third order linear ordinary differential equation

QUESTION 4

The given differential equation is;

y"-y+y^2=0

Order: The highest derivative present in this differential equation is y"

Hence it is a second order differential equation.

Linearity: There is the presence of higher power of the dependent variable, y^2. Hence the differential equation is non-linear.

Classification: Second order non-linear differential equation
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How many miles per hour is this? (one furlong is 18 mile, and a fortnight is 14 days. a furlong originally referred to the lengt
WITCHER [35]

the complete question is

While driving in an exotic foreign land you see a speed limit sign on a highway that reads 180,000 furlongs per fortnight. How many miles per hour is this? (One furlong is 1/8 mile, and a fortnight is 14 days. A furlong originally referred to the length of a plowed furrow.)

Step 1

<u>convert (furlongs per fortnight) to (miles per fortnight)</u>

180,000 furlongs per fortnight=180,000*(1/8)=22,500 miles per fortnight

Step 2

<u>convert miles per fortnight to miles per hour</u>

1 day=24 hour

14 day=24*14=336 hours

22,500 miles per fortnight=22,500/336=66.96 mph

therefore

<u>the answer is</u>

66.96 mph

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which expression finds the measure of an angle that is coterminal with a 126° angle? 126° (275n)°, for any integer n 126° (375n)
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(720n) for any integer
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In the given the figure above, m∠BAC = 64° and m∠CBA = 56°. Part I: Find the m∠DEC. Part II: Explain the steps you took to arriv
Alex17521 [72]

since the triangles are similar

angle DEC = 60 degrees


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Your tutor asks you to record the time you spend using IT during the week. You have recorded this time below: Day Time Monday 0.
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Let us convert all figures into decimals so that we can compare them easily.

Monday    0.3

Tuesday   15% = 0.15

Wednesday   1/6 = 0.1666

Thursday   0.2

Friday   1/8 = 0.125

Clearly, I spent the least amount of time on Friday using IT and the time is 0.125 or 1/8.


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2 years ago
In a survey of men aged 20-29 in a certain country, the mean height is 73.4 inches with a standard deviation of 2.7 inches. Find
satela [25.4K]

Answer:

The minimum height in the top 15% of heights is 76.2 inches.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 73.4, \sigma = 2.7

Find the minimum height in the top 15% of heights.

This is the value of X when Z has a pvalue of 0.85. So it is X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 73.4}{2.7}

X - 73.4 = 1.04*2.7

X = 76.2

The minimum height in the top 15% of heights is 76.2 inches.

3 0
2 years ago
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