Answer:
Crunchyroll or Funamation
Explanation:
Answer:
Hi LizBiz! The answer is Ctrl key on Windows, or Command key for Mac.
Explanation:
The Ctrl (Windows) key or equivalent Command key on Mac has a special purpose which allows special operations to be performed when combined with another action, such as clicking on multiple pictures or files for selection.
Answer:
B. blocking I/O
Explanation:
Most of the input and output request placed to the computer considers the blocking request. It means that the controls given cannot be returned to the given application until and unless the input/output is complete.
Thus, blocking the input/output does not return till the input and output is complete.
With a blocking I/O, the process is moved to a wait queue when the I/O request is made, and it moved backs to the ready queue as soon as the request is complete, thereby allowing the other processes to run in the meantime.
Thus (B) blocking I/O is the answer.
Answer:
// A optimized school method based C++ program to check
// if a number is composite.
#include <bits/stdc++.h>
using namespace std;
bool isComposite(int n)
{
// Corner cases
if (n <= 1) return false;
if (n <= 3) return false;
// This is checked so that we can skip
// middle five numbers in below loop
if (n%2 == 0 || n%3 == 0) return true;
for (int i=5; i*i<=n; i=i+6)
if (n%i == 0 || n%(i+2) == 0)
return true;
return false;
}
// Driver Program to test above function
int main()
{
isComposite(11)? cout << " true\n": cout << " false\n";
isComposite(15)? cout << " true\n": cout << " false\n";
return 0;
}
Explanation:
Answer:
public class IntegerToBinary
{
public static void main(String[] args) {
integerToBinary(6);
}
public static void integerToBinary(int num){
while(num > 0){
System.out.print(num%2);
num = Math.floorDiv(num, 2);
}
}
}
Explanation:
*The code is in Java.
Create a function called integerToBinary that takes one parameter, num
Inside the function, create a while loop that iterates while the num is greater than 0. Inside the loop, print the num%2. Then, get the floor division of the num by to and assign it to the num.
Inside the main, call the function with parameter 6.
