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gizmo_the_mogwai [7]

2 years ago

3

Write the equation 5x-2/2-19x+6/2x=3x-2/4 in general quadratic form. 7x 210x 2 - 39x - 10 = 0 7x 2 - 40x - 12 = 0 7x 2 - 40x + 6

= 0

2 answers:

Vladimir79 [104]2 years ago

6 0

Answer:

$7x^2 - 40x + 12 = 0$

Step-by-step explanation:

The equation $\frac{5x-2}{2}-\frac{19x-6}{2x}=\frac{3x-2}{4}$ can be written as a quadratic with the following steps:

Multiply each term by 4x to clear all denominators.
Apply the distributive property.
Combine like terms.
Move all terms to one side.

Step 1 :

$\frac{5x-2}{2}-\frac{19x-6}{2x}=\frac{3x-2}{4}\\4x(\frac{5x-2}{2}-\frac{19x-6}{2x}=\frac{3x-2}{4})\\2x(5x-2) -2(19x-6) = x(3x-2)$

Step 2:

$2x(5x-2) -2(19x-6) = x(3x-2)\\10x^2 - 4x - 38x + 12 = 3x^2 - 2x$

Step 3:

$10x^2 - 4x - 38x + 12 = 3x^2 - 2x\\10x^2 - 42x + 12 = 3x^2 - 2x$

Step 4:

$10x^2 - 42x + 12 = 3x^2 - 2x\\7x^2 - 40x + 12 = 0$

Rufina [12.5K]2 years ago

5 0

Answer:

7x-40x-12=0

Step-by-step explanation:

I know because I got it wrong following on of the other mentally disabled individuals who posted an innacurate answer here. Your welcome for an accurate answer from a semi intelligent individual. : )

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Answer:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808$

And the answer for this case would be :

$s= 3.81$ after round the value

Step-by-step explanation:

We have the following data set given:

31, 33, 36, 41, 34

If we want to find the standard deviation we need to find first the sample mean with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35$

Now we can find the sampel deviation with this formula:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808$

And the answer for this case would be :

$s= 3.81$ after round the value

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Afina-wow [57]

The second question:

Consider the division expression $7\frac{1}{2} / 2$ . Select all multiplication equations that correspond to this division expression.

$2 * ? = 7\frac{1}{2}$ $7\frac{1}{2} * ?= 2$ $? * 2 = 7\frac{1}{2}$

$2* 7\frac{1}{2} = ?$ $? * 7\frac{1}{2} = 2$

Answer:

1. See Explanation

2. $2 * ? = 7\frac{1}{2}$ and $? * 2 = 7\frac{1}{2}$

Step-by-step explanation:

Solving (a):

Given

$Students = 60$

$Group = Equal\ Sized$

Required

Interpret $\frac{60}{5}$ in 2 ways

<u>Interpretation 1:</u> Number of groups if there are 5 students in each

<u>Interpretation 2:</u> Number of students in each group if there are 5 groups

<u>Solving the quotient</u>

$Quotient = \frac{60}{5}$

$Quotient = 12$

<u>For Interpretation 1:</u>

The quotient means: 12 groups

<u>For Interpretation 2:</u>

The quotient means: 12 students

Solving (b):

Given

$7\frac{1}{2} / 2$

Required

Select all equivalent multiplication equations

Let ? be the quotient of t $7\frac{1}{2} / 2$

So, we have:

$7\frac{1}{2}/2 = ?$

Multiply through by 2

$2 * 7\frac{1}{2}/2 = ? * 2$

$7\frac{1}{2} = ? * 2$

Rewrite as:

$? * 2 = 7\frac{1}{2}$ --- This is 1 equivalent expression

Apply commutative law of addition:

$2 * ? = 7\frac{1}{2}$ --- This is another equivalent expression

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