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dimaraw [331]
2 years ago
9

If 5t = 3p what is the ratio of t to p

Mathematics
1 answer:
ratelena [41]2 years ago
4 0
All you have to do is put it in fraction form, this is the answer: 5/t=3/p
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At a red-tag sale, all items with red tags have been marked down by 49%. What should be the sale price of a DVD player having a
vampirchik [111]
Original price was $234.95
49% marked down = $234.95 *49 / 100 = $115.13

So now the sale price = original price - price of 49% marked down

sale price = $234.95 - $115.13 = $119.82

Answer: sale price of a DVD player having a red tag marked down by 49% should be $119.82
8 0
2 years ago
The area of a rectangle is (27x5 + 9x4 - 18x3) square feet. The width of the rectangle is 9x2 feet. What is the length of the re
Yuliya22 [10]
If the width is 9x², then the length is 27x^5+9x^4-18x^3/9x², which equals 3x³+x²+2x. ☺☺☺☺
8 0
2 years ago
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Find the area of triangle ABC. A = 21.67°, b = 17.2 m, c = 7.1 m
Vesna [10]

\textrm{area} = \frac 1 2 b c \sin A

= (1/2) (17.2) (7.1) sin (21.67)

= 22.5470 square meters

7 0
2 years ago
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Chris has a large collection of hockey cards and wants to get rid of some of his hockey cards he gives 2 cars away on day 1,4 ca
Marizza181 [45]

Answer:

I'm not sure for which answer you're asking for so I'll give you all of them.  On the tenth day, Chris will give away 1024 cards.

Step-by-step explanation:

On the fourth day he will give away 16, on the fifth day 32, on the sixth day 64, on the seventh say 132, on the eighth day 264, on the ninth day 528, and on the tenth day 1024

6 0
2 years ago
Consider a data set with at least three data values. Suppose the highest value is increased by 10 and the lowest is decreased by
bulgar [2K]

Answer:

a. Mean doesn't change.

b. Median doesn't change.

c. Mode can change.

Step-by-step explanation:

Let us assume the data set with 10 observations

{2,6,4,3,2,6,4,9,4,7}.

Arranging data set in ascending order

{2,2,3,4,4,4,6,6,7,9}

mean=2+2+3+4+4+4+6+6+7+9/10=4.7

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Mode

The most repeated value is 4. So, mode is 4 for assumed data.

Increasing highest value by 10 and decreasing lowest value by 10

{-8,2,3,4,4,4,6,6,7,19}

a.

mean=-8+2+3+4+4+4+6+6+7+19/10=4.7

Mean doesn't change

b.

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Median doesn't change

c.

Most occurring value is still 4. But mode can change if the value the highest value becomes most concurring value.

5 0
2 years ago
Read 2 more answers
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