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GarryVolchara [31]
2 years ago
12

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Mathematics
2 answers:
Aneli [31]2 years ago
6 0

Answer:

x+1/4x+3/2x>22

x>8

Step-by-step explanation:

Ghella [55]2 years ago
4 0

Answer:  The required inequality is x+\dfrac{1}{4}x+\dfrac{3}{2}x>22. and its solution is x>8.

Step-by-step explanation:  Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written \frac{1}{4} as many articles as Mustafa has and Gia has written \frac{3}{2} as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper.  Also, to solve the inequality.

Since m denotes the number of articles that Mustafa could have written. Then, according to the given information, we have

x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.

And the solution of the above inequality is as follows :

x+\dfrac{1}{4}x+\dfrac{3}{2}x>22\\\\\\\Rightarrow \dfrac{4x+x+6x}{4}>22\\\\\\\Rightarrow 11x>88\\\\\Rightarrow x>\dfrac{88}{11}\\\\\Rightarrow x>8.

Thus, the required inequality is x+\dfrac{1}{4}x+\dfrac{3}{2}x>22. and its solution is x>8.

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Step-by-step explanation:

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2 years ago
How would u find 4 1\5 divided by 2 1\3
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Remmber
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
conver to improper

4 and 1/5=20/5+1/5=21/5
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3 0
1 year ago
Read 2 more answers
a lunch stand makes a $.75 profit on each chef's salad and $1.20 profit on each caesar salad. On a typical weekday, it sells bet
tangare [24]

Answer:

<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>

Step-by-step explanation:

Suppose, the number of Chef's salad is x and the number of Caesar salad is y

On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.

So, the two constraints are:  40\leq x\leq 60 and  35\leq y\leq 50

The total number sold has never exceed 100 salads. So, another constraint will be:   x+y\leq 100

According to the graph of the constraints, the vertices of the common shaded region are:  (40,35), (60,35), (60,40), (50,50) and (40,50)   <em>(Refer to the attached image for the graph)</em>

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be:  P=0.75x+1.20y

For  (40, 35) ,   P=0.75(40)+1.20(35)=72

For  (60, 35) ,   P=0.75(60)+1.20(35)=87

For  (60, 40) ,   P=0.75(60)+1.20(40)=93

For  (50, 50) ,   P=0.75(50)+1.20(50)=97.5 <u><em>(Maximum)</em></u>

For  (40, 50) ,   P=0.75(40)+1.20(50)=90

Profit will be maximum when x=50 and y=50

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

6 0
2 years ago
The age distribution of a sample of part-time employees at Lloyd's Fast Food Emporium is: Ages Number 18 up to 23 6 23 up to 28
Paraphin [41]

Answer:

Option B

Step-by-step explanation:

Options for the given question -

A. A histogram

B. A cumulative frequency table

C. A pie chart

D. A frequency polygon

Solution

Option B is correct

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1 year ago
What is the sum of 9.8 and 573.54
Setler79 [48]
583.34 Youre Welcome!
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