shanti wrote the predicted values for a data set using the line of best fit y = 2.55x – 3.15. she computed two of the residual v
2 answers:
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Answer:
Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges
Step-by-step explanation:
Cost of one pound of Apple = $2x
Cost of one pound of Grapes = $(6x-5)
Cost of one pound of Oranges = $(x+2)
A shopper purchases one pound each of apples, grapes, and oranges and spends $10.50.
It can be written as:
We need to find how much the shopper spend on each fruit.
First we need to find value of x by solving equation
Solving:
The value of x is: x=1.5
Now finding cost of one pound each fruit by putting x=1.5
Cost of one pound of Apple = $2x = 2(1.5) = $3
Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4
Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5
So,
Cost of one pound of Apple = $3
Cost of one pound of Grapes = $4
Cost of one pound of Oranges = $3.5
So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges
Answer:
11.70% probability someone will spend no more than 30 minutes reading online national news reports.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability someone will spend no more than 30 minutes reading online national news reports?
This is at most 30 minutes, so 30 or less minutes. This is the pvalue of Z when X = 30.
So
has a pvalue of 0.1170.
So there is a 11.70% probability someone will spend no more than 30 minutes reading online national news reports.