It's letter A - Obligate anaerobe.
<em>Obligate anaerobes</em> are microorganisms killed by normal atmospheric concentrations of oxygen. A <em>facultative anaerobe</em> prefers to produce energy in the presence of oxygen but can survive without it. <span>A <em>photoautotroph </em>is an organism that converts light energy into chemical energy. </span><span>Prokaryotes may perform </span>aerobic<span> (oxygen-requiring) or </span>anaerobic<span> (non-oxygen-based) metabolism and some can switch between these modes. Since we're talking about an environment without oxygen and dies when exposed to oxygen, the preferable answer is A.</span>
Answer:
Placing salty water in A and distilled water in B.
Explanation:
The fastest net rate of water movement into the A-side will occur if we place salty water on that side and distilled water in the other one. The reason for this is that the A-side contains a higher concentration of solute than B. So, the water will pass the semipermeable membrane and go to the A-side to valance the concentrations on both sides. As we can see, there is an increase in the net rate of water movement into A.
Answer;
- 1.2 nM
Explanation;
-Smallest Km means highest affinity, can bind substrate better at lower concentrations. The relationship between rate of reaction and concentration of substrate depends on the affinity of the enzyme for its substrate. This is usually expressed as the Km (Michaelis constant) of the enzyme, an inverse measure of affinity
-Km is therefore, the concentration of substrate which permits the enzyme to achieve half Vmax. An enzyme with a high Km has a low affinity for its substrate, and requires a greater concentration of substrate to achieve Vmax.
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