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lesantik [10]
2 years ago
5

Find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be

low.
A.682
B.2044
C.2048
D.678
Biology
1 answer:
atroni [7]2 years ago
5 0
First, we need to solve for the common ratio from the data given by using the equation.

a(n) = a(1) r^(n-1)
1024 = 4 r^(9-1)
256 = r^8
r = 256^(1/8)
r = 2

Then, we can find the sum by the expression:

S(n) = a(1) ( 1 - r^n) / 1-r
S(9) = 4 (1 - 2^9) / 1-2
S(9) = 2044

Therefore, the correct answer from the choices listed above is option B.
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<u>Answer:</u>

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<u>Explanation:</u>

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In this example, we used lotka-volterra equations to model populations of rabbits and wolves. let's modify those equations as fo
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Answer:

Wolves absence would lead the rabbit population to become stable at 5,000.

Explanation:

Step 1. Concept

If there is a missing variable that should be in the system, set that particular variable to zero and make the necessary conclusion.

Step 2. Given,

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

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Step 3. Calculation

The transformed equations of populations of rabbit and wolves will be

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

dW/dt = −0.02W + 0.00002RW

Let's check the rabbit population in the absence of wolves(W) to 0

Thus,

Differential equation dR/dt

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

Take W to equal to O

dR/dt = 0.08R(1 - 000.2R) - 0.001R(0)

dR/dt = 0.08R(1 - 000.2R)

When,

dR/dt = 0 we have R = 0 or R = 5,000

This,

R = 5,000 becomes the equilibrium point in the absence of wolves

Then,

0 < R < 5,000, dR/dt > 0

For R, let's estimate a value rise of the rabbit population to 5,000

Then,

R > 5,000, dR/dt < 0

Judging from the value if R, we infer a deduction in the rabbit population by 5,000

Thus,

We can conclude that wolves absence would lead the rabbit population to become stable at 5,000.

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dimulka [17.4K]
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