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frozen [14]
2 years ago
5

Steve can train 48 dogs in 6 hours. How many dogs can Steve train in 10 hours?

Mathematics
2 answers:
yaroslaw [1]2 years ago
5 0

Answer:

80

Step-by-step explanation:

natita [175]2 years ago
5 0

Steval train 80 dogs in 10 hours because 48÷6 = 8 so if you do 10 times a day you get 80 so you will get a total of 80 dogs in 10 hours

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An element with mass 730 grams decays by 27.6% per minute. How much of the element is remaining after 12 minutes, to the nearest
Korolek [52]
\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=I(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &730\\
r=rate\to 27.6\%\to \frac{27.6}{100}\to &0.276\\
t=\textit{elapsed time}\to &12\\
\end{cases}
\\\\\\
A=730(1-0.276)^{12}\implies A=730(0.724)^{12}
8 0
2 years ago
Read 2 more answers
Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of
bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

                                                                                                        =\frac{7}{100}

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = 1-\frac{7}{100}

                  ⇒ prob = \frac{93}{100}

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = (\frac{93}{100})^{12}

Therefore, Probability of atleast one of 12 student has food allergies

                  = 1-(\frac{93}{100})^{12}

                  = 0.581403702521

                  ≈ 0.58 ( approx)

                 

8 0
2 years ago
Read 2 more answers
The perimeter of triangle ABC is 82 inches. The triangle is rotated about a line that passes through points B and D.
Musya8 [376]

Answer:

A cone with base radius of 17 in

Step-by-step explanation:

Given

Triangle ABC

Where

AB = BC = 24in

D = Midpoint of AC

Required

Which best describes the resulting three-dimensional figure?

First, the length of the third side of the triangle has to be calculated

The sides of triangle ABC are AB, AC and BC

Given that the perimeter = 82 in

AB + AC + BC = 82

Recall that AB = BC = 24in; The equation becomes

24 + AC + 24 = 82

Collect like terms

AC = 82 - 24 - 24\\AC = 34

Given that, the triangle is rotated at D, the midpoint of AC

The length of the midpoint has to be calculated

D = \frac{1}{2}AC

D = \frac{1}{2} * 34

D = \frac{34}{2}

D = 17

At this point, we can dismiss options C and D.

This is because; a triangular pyramid is formed by more than 1 triangles (at least 3 triangle) and in this case, we're dealing with only 1 triangle.

So, we have option A and B to select from.

When the triangle is rotated at point D, it generates a cone such that the radius of the cone is the distance at point D.

This implies that, a cone with base radius D is generated.

Recall that D = 17.

Hence, <em>A cone with base radius of 17 in</em>

7 0
2 years ago
Read 2 more answers
Can someone help meee???
Phoenix [80]

Answer:

Step-by-step explanation:

Couldn't really read the tables so i'd double check to make sure i'm correct

4 0
2 years ago
From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri
Leviafan [203]

Answer:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=201.77 represent the sample mean    

s=2.41 represent the sample standard deviation    

n=10 sample size    

\mu_o =200 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic

p_v represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :    

Null hypothesis:\mu = 200    

Alternative hypothesis:\mu = 200    

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

The statistic is given by:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

4 0
2 years ago
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