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chubhunter [2.5K]

2 years ago

3

Stefan's family rented a rototiller to prepare an area in their backyard for spring planting. The rental company charged an init

ial fee of $43 with an additional fee per hour. If they paid $64 after renting the rototiller for 7 hours, what was the hourly fee?

2 answers:

drek231 [11]2 years ago

6 0

Answer:

The hourly fee is $ 3.

Step-by-step explanation:

Given,

The initial fee = $ 43,

Let x be the additional hourly fee ( in dollars ),

Thus, the total additional fee for 7 hours = 7x dollars,

And, the total fee for 7 hours = Initial fee + Additional fee for 7 hours

= ( 43 + 7x ) dollars,

According to the question,

43 + 7x = 64

7x = 21 ( Subtracting 43 on both sides )

x = 3 ( Divide both sides by 7 )

Hence, the hourly fee is $ 3.

taurus [48]2 years ago

6 0

3rd Option: 7h + 43 =64

2nd Option: $3

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Which statement is true regarding the functions on the graph?

Mrrafil [7]

Answer: f(3)=g(3)
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2 years ago

Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 mo

Katarina [22]

Given:

Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 monthly service fee. Paco is trying to keep his bill for the month below $30.

To Find:

The number of texts 't' Paco can send/receive in a month.

Answer:

$0\leq t$

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

Step-by-step explanation:

Paco wants to keep is monthly bill below $30.

We see that he has to pay a foxed monthly service fee of $15. This means he is only left with a limit of $30 - $15 = $15 for his monthly calls and texts.

That is, the amount he has to pay for texting and calling has to be less than $15.

For texts, the cell phone carrier charges $0.20 for sending/receiving texts.

For calls, he is charged $0.15 per minute.

Let the number of text messages Paco can send or receive in a month be denoted by 't'.

Let the number of minutes Paco can call in a month be denoted by 'c'.

Then, the total cost of text messages he can send or receive per month would be 0.20t and the total cost of the minutes he spends on calls would be 0.15c. Together, the sum of these has to be less than $15 if his monthly bill has to be kept less than $30 (accounting for the monthly service fee).

So,

$0.20t+0.15c$

The number of texts he can send will dpend on the number of minutes he spends on his calls. For Paco to spend maximum number of texts, he has to spend 0 minutes on calls.

So, putting c = 0, the aboce equation can be written as

$0.20t+0$

That is, Paco has to send and receive less than 75 texts.

So,

$0\leq t$

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

3 0

2 years ago

Read 2 more answers

2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.

vova2212 [387]

Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

$a_1 = 2.8$

$a_2 = 3.4$

Common difference = $a_2 - a_1 = 3.4 - 2.8 = 0.6$ .

Expression for the nth term:

$a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n$

n = 50 for the fiftieth term. Therefore

$a_{50} = 2.2 + 0.6 \times 50 = 32.2$ .

6 0

2 years ago

Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll

JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

$\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

$Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

So, the possibility of getting a total of 7 = $\frac{6}{36}=\frac{1}{6}$

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = $\frac{2}{36}$ = $\frac{1}{18}$

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = $\frac{28}{36}$ = $\frac{7}{9}$

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

$\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11$

$\frac{11}{3}+\frac{11}{3}-\frac{77}{9}$

$\frac{22}{3}-\frac{77}{9}$

$\frac{66-77}{9}$

$-\frac{11}{9}$

$-1.22$

Therefore the expected payoff for this game is -$1.22.

4 0

2 years ago

From 1994 to 1995 the sales of a book decreased by 80%. If the sales in 1996 for the same as in 1994, By what percent did the in

zheka24 [161]

Answer:

400%

Step-by-step explanation:

Let the sales be "100" in 1994

Since, it decreased 80%, the sales was:

80% = 80/100 = 0.8

0.8 * 100 = 80 (decreased by 80)

So, it was

Sales in 1995: 100 - 80 = 20

Sales in 1996 was same as in 1994, so that's 100

Thus,

Sales in 1994: 100

Sales in 1995: 20

Sales in 1996: 100

We need to find percentage increase form 1995 to 1996, that is what percentage increase is from 20 to 100?

We will use the formula:

$\frac{New-Old}{Old}*100$

Where

New is 100

Old is 20

SO, we have:

$\frac{New-Old}{Old}*100\\=\frac{100-20}{20}*100\\=4*100\\=400$

So, it increased by 400%

3 0

2 years ago