Given: LMNB is a square, LM = 20cm, P∈ LM , K ∈ PN , PK = 1 5 PN, LP = 4 cm Find: Area of LPKB
1 answer:
Answer:
80 cm²
Step-by-step explanation:
Trapezoid LPKB has area ...
A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²
Triangle BPN has area ...
A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²
Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:
ΔBKN = (4/5)(200 cm²) = 160 cm²
The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...
240 cm² - 160 cm² = 80 cm²
You might be interested in
Answer:
See explanation
Step-by-step explanation:
The lateral surface area of a cylinder is calculated using:
We have that the lateral surface area is about, 80 square inches.
Assuming the radius is 10 inches, then we substitute r=10, π=3.14 and solve for h.
We solve for h to get:
<span>Given the
table that shows the hair lengths y (in inches) of your friend and her cousin in different months x.
Month Friends Hair(in) Cousins Hair(in)
3 4 7
8 6.5 9.
To solve for the cousins hair, recall that the equation of a line is given by
y = mx + c
From the table,
7 = 3m + c . . . (1)
9 = 8m + c . . . (2)
(1) - (2) ⇒ -2 = -5m
Substituting for m into equation (1) gives:
Therefore, the equation representing the growth of the cousin's hair is given by y = 1.2x + 5.8
</span>
Month Friends Hair(in) Cousins Hair(in)
3 4 7
8 6.5 9.
To solve for the cousins hair, recall that the equation of a line is given by
y = mx + c
From the table,
7 = 3m + c . . . (1)
9 = 8m + c . . . (2)
(1) - (2) ⇒ -2 = -5m
Substituting for m into equation (1) gives:
Therefore, the equation representing the growth of the cousin's hair is given by y = 1.2x + 5.8
</span>