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marta [7]
2 years ago
4

What is 257, 166 cm3 rounded to the nearest hundred thousand?

Mathematics
1 answer:
Anton [14]2 years ago
5 0

ANSWER

300,000 cm³

EXPLANATION

We want to round

257, 166 {cm}^{3}

to the nearest hundred thousand.

The digit in the hundred thousand position is '2'

The immediate digit to it's right is 5.

So we round up to obtain

300,000 cm³

Therefore, 257,166 cm³ rounded to the nearest hundred thousand is 300,000 cm³

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Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zarrin [17]

Correction:

Because F is not present in the statement, instead of working on​P(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

So

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0
2 years ago
The random variable x is said to have the yule simon distribution if
balu736 [363]
The Yule-Simon distribution is a discrete probability distribution. It is named after Udny Yule and Herbert A. Simon. 

The Yule–Simon distribution was originally created by Yule as a limiting distribution model for a particular stochastic process, called the "Yule process" or the "preferential attachment process," in his study of the distribution of biological taxa and subtaxa.

The random variable X is said to have the Yule-Simon distribution if 

P (X=k) =  <u>            4              </u>      where   k = 1,2,...<u>
</u>
                     k (k+1)(k+2)

4 0
2 years ago
Julia went into a movie theater and bought 2 bags of popcorn and 5 pretzels, costing
andreyandreev [35.5K]

Answer:

A bag of pop corn costs $8, and each Pretzel costs $4.25.

Step-by-step explanation:

Let b be the price of popcorn, and p the price of Pretzels. If the girl bought 2 bags of popcorn and 5 Pretzels and it cost her $37.25, we have the equation

2b+5p=37.25  <em>(this says that the cost of 2 popcorn bags plus 5 pretzels equals $37.25)</em> .

And, since Zoe bought 8 popcorn bags and 9 Pretzels with a total price of $102.25, we get the equation

8b+9p=102.25<em> (this says that the cost of 8 popcorn bags plus 9 Pretzels equals $102.25).</em>

Thus, we have two equations

1. 2b+5p=37.25

2. 8b+9p=102.25

and we solve them by first multiplying equation (1) by 4:

4(2b+5p=37.25 )\rightarrow (8b+20p=149),

and then subtracting it from equation (2):

\:\:\:\:\: 8b+9p=102.25\\-(8b+20p=149)\\\line(1,0){3 cm}\\-11p=-46.75\\\\\boxed{p=\$4.25}

Now we put this value of p into equation (1) and get:

2b+5(4.25)=37.25

and we solve for b to get:

2b=37.25-21.5

\boxed{ b=8}

Therefore, a bag of popcorn costs $8, and each Pretzel costs $4.25.

8 0
2 years ago
Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on t
lilavasa [31]

Answer:

The teacher should use the median for Amo and the mean for Javier.

Complete question;

Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on the median or the mean

Test

Number

Amo’s Scores

Javier’s Scores

1

97

68

2

92

97

3

89

65

4

55

92

5

90

65

What measure of center should Mr. Malloy use for Amo and for Javier for the best possible grade?

The teacher should use the mean for both Amo and Javier.

The teacher should use the median for both Amo and Javier.

The teacher should use the median for Amo and the mean for Javier.

The teacher should use the mean for Amo and the median for Javier.

Attached is the image of their scores

Step-by-step explanation:

Amo's Score in Ascending Order: 55,89,90,92,97

Javier's Score in Ascending Order: 65,65,68,92,97

For Amo;

Mean = (55+89+90+92+97)/5 = 84.6

Median = 90

For Javier;

Mean = (65+65+68+92+97)/5 = 77.4

Median = 68

Therefore,

Median is higher for Amo and mean is higher for Javier

So, The teacher should use the median for Amo and the mean for Javier.

4 0
2 years ago
Point S is on line segment \overline{RT}
Korolek [52]
Ummm let me see so what u have to do is
7 0
2 years ago
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