Answer:
(w - 2.5)(w + 2.5)
(-4v - 9)(-4v + 9)
Step-by-step explanation:
* Lets explain what is the a difference of two squares
- If we multiply two binomial and the answer just two terms with
negative sign between them and the two terms are square numbers
we called this answer a difference of two squares
- Examples
# (a + b)(a - b)
- Lets multiply them
∵ (a × a) + (a × -b) + (b × a) + (b × -b)
∴ a² - ab + ba - b²
- Add the like term
∵ ab = ba
∴ -ab + ba = 0
∴ (a + b)(a - b) = a² - b² ⇒ difference of two squares
- From above the difference of two squares appears when we
multiply sum and difference of the same two terms
# (a + b) ⇒ is the sum of a and b
# (a - b) ⇒ is the difference of a and b
* Now lets solve the problem
- In (5z + 3)(-5z - 3)
∵ (5z + 3) ⇒ is the sum of 5z and 3
∵ (-5z - 3) ⇒ is the difference of -5z and 3
∵ 5z ≠ - 5z
∴ They are not the sum and difference of the same two terms
∴ The product result not in a difference of squares
- In (w - 2.5)(w + 2.5)
∵ (w - 2.5) is the difference between w and 2.5
∴ (w + 2.5) is the sum of w and 2.5
∴ They are the sum and difference of the same two terms
∴ The product result in a difference of squares
- In (8g + 1)(8g + 1)
∵ The two brackets are the sum of 8g and 1
∴ They are not the sum and difference of the same two terms
∴ The product result not in a difference of squares
- In (-4v - 9)(-4v + 9)
∵ (-4v - 9) is the difference between -4v and 9
∵ (-4v + 9) is the sum of -4v and 9
∴ They are the sum and difference of the same two terms
∴ The product result in a difference of squares
- In (6y + 7)(7y - 6)
∵ (6y + 7) is the sum of 6y and 7
∵ (7y - 6) is the difference between 7y and 6
∵ 6y ≠ 7y and 7 ≠ 6
∴ They are not the sum and difference of the same two terms
∴ The product result not in a difference of squares
- In (p - 5)(p - 5)
∵ The two brackets are the difference of p and 5
∴ They are not the sum and difference of the same two terms
∴ The product result not in a difference of squares
