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Anon25 [30]
2 years ago
13

To the nearest degree, what is the measure of the central angle for faucets? 37° 24° 48° 43°

Mathematics
2 answers:
Masteriza [31]2 years ago
4 0

Answer:

\large\boxed{43^o}

Step-by-step explanation:

\text{Faucets}\to12\%\\\\p\%=\dfrac{p}{100}\to12\%=\dfrac{12}{100}=0.12\\\\12\%\ \text{of}\ 360^o\to0.12\cdot360^o=43.2^o\approx43^o

vazorg [7]2 years ago
4 0

Answer: 43^{\circ}

Step-by-step explanation:

From the given pie-chart, the percentage for faucets = 12 %

We know that every circle has angle of 360^{\circ}.

Now, the central angle for faucets is given by :-

\text{Central angle}=\dfrac{\text{Percent of Faucets}}{\text{100}}\times360^{\circ}\\\\\Rightarrow\ \text{Central angle}=\dfrac{12}{100}\times360^{\circ}=43.2^{\circ}\approx43^{\circ}

Hence, the measure of the central angle for faucets \approx43^{\circ}

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Find the range of y=3/2cos4x-1
MrRissso [65]

Answer:

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

Step-by-step explanation:

Smallest value of cos α = - 1,

largest value of cos α = 1.

When cos 4x = - 1,  y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5

When cos 4x = 1,  y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

5 0
2 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

7 0
2 years ago
Interpret the graph to determine the statement the manager at a building supply store can use to help a customer determine how m
svp [43]

Answer:

Each gallon of primer will cover a maximum of 200 square feet

Step-by-step explanation:

The x-axis of the graph is the area to paint in square feet.  The y-axis of the graph is the number of gallons of primer needed.

We can see that 1 gallon of primer covers from 0 to 200 feet; 2 gallons of primer covers from 200 to 400 feet; etc.

This tells us that each gallon of primer covers a maximum of 200 square feet.

8 0
2 years ago
Read 2 more answers
Divide 32x4 − 12x2 + 7x by 2x.
Katen [24]
(32x⁴ - 12x² + 7x) / 2x

32x⁴/2x - 12x²/2x + 7x/2x

16x³ - 6x + 7/2
4 0
2 years ago
A 90 k g shopper is standing on an escalator that makes a 25 ∘ incline with the horizontal. The escalator carries the shopper to
Nitella [24]

Answer:

W= 27 k J

Step-by-step explanation:

Given that

mass ,m = 90 kg

Height , h= 30 m

angle , θ = 25°

The work done by escalator is given as follows

W  = m g h

Work done by escalator does not depends on the angle ,it depends only on  height.

Now by by putting the values in the above equation we get

W= 90 x 10 x 30 J            ( take g = 10 m/s² )

W= 27000 J

W= 27 k J

Therefore work done by escalator will be 27 k J.

8 0
2 years ago
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