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lukranit [14]
2 years ago
11

An indoor sport exhibition is coming to the arena. Your supervisor has asked you to help set up a handball pitch and seating are

a as shown in the plan view below..
Use the following formulae:

Perimeter of a rectangle = 2l + 2w

Circumference of a circle = πd

π = 3.14

Area of a rectangle = lw

Area of a circle = πr²

What is the total perimeter of the pitch and seating area?
m

What is the total area of the pitch and seating area?

m2

Mathematics
1 answer:
Sphinxa [80]2 years ago
3 0

Answer:

Perimeter: 174.8 m

Area: 1,394 sq m

Step-by-step explanation:

First, the perimeter.

Before we start, let's calculate the circumference of the half-circles at the ends of the field.

The measurement says 2,000 cm, so let's convert it to 20 m for ease.

Circumference of a circle: πd, where d = diameter.. in our case d = 20 m

Circumference of a 20m diameter circle: 20π = 62.8 m

We have 2 half circles... so the perimeter of each half-circle will be: 31.4 m

We also have 800 cm measurement for the "height" of the seating areas... let's convert that in 8 m

We also need to find out the space between the seating area...  We know the whole rectangular pitch is 40 m, then we have to subtract the width of both seating areas (20 and 15 m)... so the space between them is 5m

So, starting with the upper left corner of the rectangular pitch, and working our way clockwise, we encounter the following lengths:

P = 40 + 31.4 + 8 + 10 + 8 + 5 + 8 + 25 + 8 + 31.4 = 174.8 m

The total perimeter is then of 174.8 m

For the area, we need to calculate the area of all forms:

Large rectangular pitch:

LR = 40 x 20 = 800 sq m

The two half circles, form a circle, so A = πr², where r is the radius, which is half the diameter.

AC = π (10)² = 100 π = 314 sq m

Then the seating areas:

SA1 = 25 x 8 = 200 sq m

SA2 = 10 x 8 - 80 sq m

Then, we add up everything:

TA = LR + AC + SA1 + SA2

TA = 800 + 314 + 200 + 80 = 1,394 sq m

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A stick of length l is broken at a uniformly chosen random location. We denote the length of the smaller piece by X. (a) Find th
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Which statements are true regarding the relationships between central, inscribed, and circumscribed angles of a circle? Check al
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Answer:

# A circumscribed angle is created by two intersecting tangent segments ⇒ true (1st answer)

# The measure of a central angle will be twice the measure of an inscribed angle that intercepts the same arc ⇒ true (3rd answer)

# The measure of a central angle will be equal to the measure of an inscribed angle when the arc intercepted by the inscribed angle is twice as large as the arc intercepted by the central angle ⇒ true (6th answer)

Step-by-step explanation:

* Lets revise the types of angles in a circle

- A circumscribed angle is the angle made by two intersecting

 tangent lines to a circle (it's out side the circle)

- Its measure is half the difference of the measures of the two

 intercepted arcs

- Ex:

∵ AB and AC are tangent to circle M at B and C

∴ ∠A is a circumscribed angle

∴ m∠A = 1/2(m major arc BC - m minor arc BC)

- An inscribed angle is an angle formed by two chords in a circle

  which have a common endpoint, this common endpoint is the

  vertex of it

- Its measure is half the measure of the intercepted arc

Ex:

∵ XY and XZ are two chords in circle M

∴ ∠YXZ is an inscribed angle subtended by arc YZ

∴ m∠YXZ = 1/2 (m arc YZ)

- A central angle is an angle with endpoints located on the

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- Its measure is the measure of the intercepted arc

- Ex:

∵ MA and MB are two radii of circle M

∴ ∠AMB is a central angle subtended by the opposite arc AB

∴ m∠AMB = m of arc AB

- The measure of an inscribed angle is half the measure of the

  central angle which subtended by the same arc

- Ex:

∵ ∠ABC is an inscribed angle in circle M subtended by arc AC

∵ ∠AMC is a central angle subtended by arc AC

∴ m∠ABC = 1/2 m∠AMC

∴ m∠AMC = 2 m∠ABC

* Lets solve the problem

- From the facts above:

# A circumscribed angle is created by two intersecting tangent

  segments ⇒ true

# The measure of a central angle will be twice the measure of an

   inscribed angle that intercepts the same arc ⇒ true

- Lets prove the last statement

∵ AMC is a central angle of circle M subtended by arc AC

∴ m∠AMC = m of arc AC ⇒ (1)

∵ XYZ is an inscribed angle of circle M subtended by arc XZ

∴ m∠XYZ = 1/2 m of arc XZ

∵ m of arc XZ is twice m of arc AC

∴ m∠XYZ = m of arc AC ⇒ (2)

- From (1) and (2)

∴ m∠AMC = m∠XYZ

∴ The statement down is true

# The measure of a central angle will be equal to the measure of

   an inscribed angle when the arc intercepted by the inscribed

   angle is twice as large as the arc intercepted by the central

   angle ⇒ true

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2 years ago
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