Question

What value of b will cause the system to have an infinite number of solutions? y = 6x – b –3x + y = –3 b = 2 4 6 8

Answer 1

Answer with explanation:

The two equations in two variables are

1.→y=6 x-b

6 x -y =b

2.→ -3 x +y= -3

⇒Equations

1.→ Ax +B y=C

2.→ P x +Q y=R

will have infinite number of Solutions if,

    $\frac{A}{P}=\frac{B}{Q}=\frac{C}{R}$

→The equation 1 and equation 2 , has infinite number of Solution, if

$\rightarrow \frac{6}{-3}\neq \frac{-1}{1}\\\\\rightarrow -2\neq -1$

So, there is no such value of b is Possible.

 

Answer 2

The correct question is

 What value of b will

cause the system to have an infinite number of solutions?

For

y = 6x – b   and  -3x+(1/2)y=-3

 we have that

y = 6x – b   ---------> equation

1

-3x+(1/2)y=-3--------->  -6x+y=-6------ > -2x+y=-3------- > y=6x-6

y=6x-6------>

equation 2

 we know that

For the system to have an infinite number of solution,

equation 1 must be equal to equation 2

so

6x – b=6x-6-------> 6x-6x=b-6---------> b=6

 the answer is b=(6)