Question

Square EFGH stretches vertically by a factor of 2.5 to create rectangle E?F?G?H?. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H? ?

Answer 1

Answer: (-5,0)

Step-by-step explanation:

Given : Square EFGH stretches vertically by a factor of 2.5 to create rectangle  E?F?G?H?.

The square stretches with respect to the x-axis such that the point H is located at (-2, 0).

Since , we know that to find the coordinate of image , we multiply the scale factor to the coordinate of pre-image.

Then , the coordinate of H? is given by :-

$(-2\times2.5, 0\times2.5)=(-5,0)$

Answer 2

Answer with explanation:

Pre-image =Rectangle EFGH

Image = Rectangle E'F'G'H'

Stretch Factor = 2.5

Coordinates of Point H= (-2,0)

If Coordinate of any point is (x,y) and it is stretched by a factor of k , then coordinate of that point after stretching = (k x , k y).

So, Coordinates of Point H' will be=(-2×2.5,0×2.5)

                                      = (-5,0)