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FromTheMoon [43]
2 years ago
13

Convert decimal +49 and +29 to binary, using the signed‐2’s‐complement representation and enough digits to accommodate the numbe

rs. then perform the binary equivalent of (+29) + (-49), (-29) + (+49), and (-29) + (-49). convert the answers back to decimal and verify that they are correct.
Mathematics
1 answer:
Serhud [2]2 years ago
5 0

To solve this problem, let us first find for the binary equivalents of the numbers. They are:

Decimal --> Binary

+ 29 --> 00011101

+ 49 --> 00110001

- 29 --> 11100011

- 49 --> 11001111

Now we apply the normal binary arithmetic to these converted numbers:

(+ 29) + (- 49) ---> 00011101 + 11001111 = 11101100 ---> - 20 (TRUE)

(- 29) + (+ 49) ---> 11100011 + 00110001 = 00010100 ---> + 20 (TRUE)

(- 29) + (- 49) ---> 11100011 + 11001111 = 10110010 ---> - 78 (TRUE)

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A curious student asks his math teacher: "I heard you have three daughters. How old are they?" The math teacher says: "Well, the
scZoUnD [109]

Answer:

There are 7 solutions.

The possible answers are:

The oldest daughter is 72 and the others are 1 and 1 and the room number is 74.

The oldest daughter is 36 and the others are 1 and 2 and the room number is 39.

The oldest daughter is 24 and the others are 1 and 3 and the room number is 28.

The oldest daughter is 18 and the others are 1 and 4 and the room number is 23.

The oldest daughter is 12 and the others are 2 and 3 and the room number is 17.

The oldest daughter is 12 and the others are 1 and 6 and the room number is 19.

The oldest daughter is 9 and the others are 1 and 8 and the room number is 18.

The first few solutions are laughable and unlikely, but all are possible.  

OR..

The clue that the sums of the daughters' ages is the room number is the sleeper.  The student's first response is that two possible age combinations meet the necessary conditions.  The teacher's reference to the "oldest daughter" resolves the ambiguity, so one of the solutions must consist of a set of ages in which at least two of the oldest daughters are the same age.

The prime factors of 72 are 2^3 *3^2.  Because one of the solutions requires the two oldest daughters to be the same age, only combination 6, 6, 2 would be admissible.  There are insufficient factors for any other combination in which the duplicate ages represent the oldest daughter.  The ages of these daughters sum to 14, which is the room number.  The other combination must therefore add to 14 and have an unique oldest age.  The combination 8, 3, 3 meets all conditions and is the answer.

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2 years ago
The regular hexagon has a radius of 4 in. What is the approximate area of the hexagon? 24 in.2 42 in.2 48 in.2 84 in.2
masha68 [24]
The central angle of a hexagon is 60°. Dividing it by two will give us 30°. The side opposite to 30° is 2 inches, multiplied by 2 is 4 inches. Thus, each side of the hexagon is 4 inches. Also, the apothem is 2sqrt(3). The area of the figure is calculated through the equation,
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where a is apothem and P is perimeter
Substituting,
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The answer is approximately 41.57 in².
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If ray JG is an angle bisector of ∠FJH, find m∠FJH.
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Answer:

m∠FJH=60°

Step-by-step explanation:

The complete question is

JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°  

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we know that

m∠FJH=m∠FJG+m∠GJH -----> equation A

If ray JG is an angle bisector of ∠FJH

then

m∠FJG=m∠GJH -----> equation B

substitute the given values in equation B and solve for x

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substitute the value of x

m∠FJH=(2(13) + 4)°+(3(13) -9)°

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m∠FJH=60°

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It’s c multiply by 2 on both sides
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