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2 years ago

Charlie bought a car for 5% off the selling price of $7,200. The sales tax for his state is 3.4%. How much is the sales tax?

Mathematics

2 answers:

Tcecarenko [31]2 years ago

6 0

If it is 5% off, then ur paying 95%

0.95(7200) = 6840......sales tax = 3.4% of 6840 = 0.034(6840) = 232.56

dedylja [7]2 years ago

5 0

5% of 7200 is 360. Subtract 360 from 7200 to get 6840. The sales tax (3.4%) of 6840 is 232.56.

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Suppose the function H(t) gives the heart rate of a runner at various points in time (in minutes) during a 5 mile run, which tak

Marrrta [24]

Answer:

[0, 57.5]

OR

0 - 57.5

Step-by-step explanation:

Given the function $H(t)$ which gives the heart rate as per time.

That means Heart rate of the runner changes according to time.

$H(t)$ is a function which takes Time as input as observed by the function's representation. In bracket, there is $t$ .

That also means time $t$ is the input to the function $H(t)$ .

It is also given that during the time as the runner runs, the heart beat will change.

The output of the given function will be Heart beat of the runner.

Time taken to complete the run is given as 57 minutes and 30 seconds.

Domain of a function is the valid inputs that can be given to the function for which the output of the function is defined.

Here, time in minutes is the input to the function.

So, maximum time can be 57.5 minutes.

And as the runner will start from the time = 0 minutes

So, the valid inputs can be from 0 to 57.5 minutes.

Therefore, the domain is [0, 57.5]

OR

0 - 57.5

5 0

2 years ago

1+4=5 2+5=12 3+6=21 8+11=?

satela [25.4K]

That whole eqation is 40

6 0

2 years ago

Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).

Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

$\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).$

Then

$\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.$

2. Find

$\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).$

Then

$\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.$

3. Find

$\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).$

Then

$\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.$

$\angle E=\arccos0=\dfrac{\pi}{2},\\ \\
\angle D=\arccos\letf(\sqrt{\dfrac{37}{83}}\right)\approx 0.27\pi,\\ \\
\angle F=\arccos\letf(\sqrt{\dfrac{46}{83}}\right)\approx 0.23\pi.$