All categories

2 years ago

How much would it cost to buy 100 shares in ODX group Inc and 300 shares

Mathematics

1 answer:

insens350 [35]2 years ago

7 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The cost to buy 100 shares in ODX group Inc and 300 shares peer Comms Lts is

$C = \$ 775$

Step-by-step explanation:

From the chat we that the cost of 100 ODX shares is $\$175$

The cost of 100 peer Comms Lts is $\$ 200$

Hence the cost 300 peer Comms Lts is $k = 3 * 200 = \$ 600$

Now the cost of 100 shares in ODX group Inc and 300 shares of peer Comms Lts is mathematically evaluated as

$C = 175 + 600$

$C = \$ 775$

You might be interested in

An audience of 450 people is seated in an auditorium. Each row contains the same number of seats and each seat in the auditorium

Kruka [31]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

SR = 450
S = 450/R 

(S - 3)(R + 5) = 450 
(450/R - 3)(R + 5) = 450 
(450 - 3R)(R + 5) = 450R 
450R + 2250 - 3R^2 - 15R = 450R 
3R^2 + 15R - 2250 = 0 
R^2 + 5R - 750 = 0 
R^2 + 30R - 25R - 750 = 0 
R(R + 30) - 25(R + 30) = 0 
(R + 30)(R - 25) = 0 
R ∈ {-30,25}

Only positive numbers make sense in this context, therefore R = 25.

5 0

2 years ago

Read 2 more answers

Literal Equations: d + 3n = 1, for n

slega [8]

D + 3n = 1 Subtract d from both sides
3n = 1 - d Divide both sides by 3
n = $\frac{1 - d}{3}$

8 0

1 year ago

The Taieri Plain in New Zealand is 6 feet below sea level (or –6 feet). If you are standing 3 feet above sea level, is your elev

Anna11 [10]

You would be 3ft above the sea level, if you are -6ft under the sea level and if you are standing 3ft “above” you would have to clime back up 9ft to get back to the positive’s which is “positive 3” so yes, your elevation will be opposite of the “plain” since you went to a -6 to a positive 3, with different numbers.

8 0

1 year ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −2y2 + 6y = −2

andrezito [222]

-2y^2 + 6y + 2 = 0
a = -2, b = 6, c = 2
x = (- b + - sqrt(b^2-4ac))/(2a)
x=(-6+-sqrt(36-4*-2*2))/-4
x=(-6+-sqrt(36+16))/-4
x=(-6+-sqrt(52))/-4
x = (-6 +- 2sqrt13)/-4
x = (3 + - sqrt13)/2

8 0

2 years ago

Read 2 more answers

A restaurant owner was experimenting with the taste of her homestyle lemon drink. She started with 60 litres of water. She remov

Burka [1]

Answer:

ratio of pure lemon juice to water in the homestyle lemon drink is 5 : 19.

Step-by-step explanation:

In order to solve the final ratio of lemon juice to water, let us start by determining the initial ratio of pure lemon juice to water in the first mix. This is done as follows:

Total volume of mixture = 60 liters

initial volume of water = 60 liters

initial volume of lemon juice = 0 liters

1) She removed 15 liters of the water and replaced it with 15 liters of pure lemon juice.

Volume of water = 60 - 15 = 45 liters

Volume of lemon juice = 15 liters

$\therefore \frac{15}{60}\ = \frac{1}{4}\ of\ the\ first\ mix\ is\ lemon\ juice\\\frac{45}{60}\ = \frac{3}{4}\ of\ the\ first\ mix\ is\ pure\ water$

2) She removed 10 liters of the new mixture

Let us convert this amount removed into ratio:

$lemon\ juice\ = \frac{1}{4}\ \times 10 = \frac{10}{4} = \frac{5}{2}\ liters.\\ \therefore the\ owner\ removes\ \frac{5}{2}\ liters\ of\ pure\ lemon\ juice\\pure\ water\ = \frac{3}{4}\ \times 10 = \frac{30}{4} = \frac{15}{2}\ liters\\ \therefore\ the\ owner\ removes\ \frac{15}{2}\ liters\ of\ water\ from\ the\ first\ mix.$

New volumes of water and lemon juice after removing the 10 liters of mixture is calculated as follows:

$lemon\ juice\ = 15 - \frac{5}{2} = \frac{30-5}{2} = \frac{25}{2}\ liters\ of\ lemon\ juice\\pure\ water\ = 45 - \frac{15}{2} = \frac{90-15}{2} = \frac{75}{2}\ liters\ of\ pure\ water$

3) and replaced it with 10 liters of water.

$New\ volume\ of\ water\ = 10 + \frac{75}{2} = \frac{20+ 75}{2} = \frac{95}{2}\ liters$

The final ratio of lemon juice to water:

$\frac{25}{2} : \frac{95}{2}\\= 25 : 95\\= 5 : 19$

Therefore, the final ratio of pure lemon juice to water in the homestyle lemon drink is 5 : 19.

4 0

2 years ago