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1 year ago

Discuss the scientific evidence that supports the idea that sexual orientation is greatly influenced by biology.

Biology

2 answers:

kow [346]1 year ago

6 0

Answer: It's in the blood

Explanation: Sexuality is usually influenced by Biology because, sexual attraction; or love in this case, is usually brought on from genes passed on from previous generations,Sexuality can also be influenced by a parent with their preferred sexuality.

Serhud [2]1 year ago

4 0

Answer:

It can be said that science implies that there is a difficult interaction between biological factors, which conditions when a person is attracted to people of the same sex, the opposite sex or both.

Explanation:

The scientific evidence identifies five possible chromosomal regions, in these variants it is shown with a significant frequency that the individuals of a sample that comment have had relations with individuals of the same sex. Although it is noted that the link between biology and homosexual behavior is very complex, since different variants appear that are different between men and women, and without an association between the presence of these genes and a high or low proportion of homosexual relationships.

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Explanation:

We have three genes in the same chromosome and are trying to determine their order and relative distance to each other.

The genes and possible alleles are:

claret (c/c+)
spineless (s/s+)
hairless (h/h+)

All mutations are recessive: two copies of the mutant allele are needed for the fly to show that trait.

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claret hairless male: $\frac{s^+\ c\ h}{s^+\ c \ h}$
spineless female: $\frac{s\ c^+\ h^+}{s\ c^+ \ h^+}$

Each parent can produce 1 type of gamete only, so the F1 will be homogeneous:

F1

$\frac{\ s\ \ \ c^+\ \ h^+}{s^+\ \ c \ \ \ h}$

During meiosis, the F1 females can produce 8 types of gametes: 2 parentals and 6 recombinants (two of them, the result of a double crossing over).

If they are test crossed to homozygous recessive males (which can only produce a $\frac{s \ c\ h}{}$ gamete), the following phenotypes are obtained (I just write the alleles they inherited from the female fly, as the ones that came from the male are the same for all of them):

321 spineless (s c+ h+) ----> Parental
309 claret, hairless (s+ c h) ----> Parental
130 claret, spineless (s c h+) ----> Recombinant
140 hairless (s+ c+ h) ----> Recombinant
32 hairless, claret, spineless (s c h) ----> Recombinant
38 WT (s+ c+ h+) ----> Recombinant
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12 hairless, spineless (s c+ h) ----> Double Recombinant

The phenotypes observed in the highest frequency are always the parentals, and the ones in the lowest frequency are always the double recombinants.

To determine the order of the genes:

we have to write down the genotype of the F1 female three times, changing the order of the genes each time.
Then, we hypothesize what the double recombinant gametes would look like.
When the theoretical double recombinants we obtain are the same as the ones observed in the F2, we know that that is the correct order of the genes.

In this problem, only if the middle gene is h+/h the double crossing over gives us the observed double recombinant gametes, therefore hairless is the middle gene.

$\frac{s\ h^+\ c^+}{s^+\ h\ c}$

Double recombinants:

s h c+ ----> spineless hairless
s+ h+ c ----> claret

To determine the distance between the genes:

Genetic distance (m.u.) = Recombination Frequency x 100

Distance between the spineless and hairless genes:

$Distance \ [s-h]= \frac{number\ of\ recombinants \ [s-h]}{Total number of individuals} * 100\\\\\\Distance \ [s-h]= \frac{32+38+12+18}{1000} * 100\\\\Distance \ [s-h]= 10\ map\ units$

Distance between the hairless and claret genes:

$Distance \ [h-c]= \frac{130+140+12+18}{1000} * 100\\\\Distance \ [h-c]= 30\ map\ units$

<h3>The gene map for these genes is:</h3>

spineless -----------------hairless ---------------------------claret

10 m.u. 30 m.u.

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