All categories

2 years ago

TW¯¯¯¯¯¯¯¯¯=14.6, CW¯¯¯¯¯¯¯¯¯=6, TU¯¯¯¯¯¯¯=21.2. Find the value of VW¯¯¯¯¯¯¯¯¯.

Mathematics

2 answers:

pogonyaev2 years ago

8 0

TW x WU = CW x VW

Fill in the known values:

WU = TU - TW = 21.2 - 14.6 = 6.6

14.6 x 6.6 = 6 x VW

Simplify:

96.36 = 6VW

Divide both sides by 6:

VW = 96.36 / 6

VW = 16.06

Round to one decimal place:

VW = 16.1

The answer is D>

WITCHER [35]2 years ago

6 0

Answer: Are you in educere geometry? If so lmk I am too

Step-by-step explanation:

You might be interested in

Write the slope-intercept form of an equation for the line passing through -2, 8 and (-4, -4)

KonstantinChe [14]

Find slope: (-4-8)/(-4+2) = -12/-2 = 6
Y = 6x + b
Plug in a point
8 = 6(-2) + b, b = 20
Equation: y = 6x + 20

6 0

2 years ago

Read 2 more answers

hree TAs are grading a final exam. There are a total of 60 exams to grade. (a) How many ways are there to distribute the exams a

nalin [4]

Answer:

a. 205320

b. 34220

c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!

Step-by-step explanation:

a) The number of ways to dustribute exams among the TA's is:

n / (n - r)!

n= number of things to choose from

r= Choosing r number

60P3= 60! / (60 - 3)!

(60)(59)(58)(57)! / (57)!

=205320

B) The number of ways to dustribute the exams among the TA's is:

n! /(n - r)! r!

60C3= 60! /(60 - 3)! 3!

= 60!/ 57! 3!

= 60 × 59 × 58 / 3 × 2 × 1

= 34220

C) The required number of ways is:

60C25 + 60C20 + 60C15

= 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!

6 0

2 years ago

Find the length of the third side of the right triangle.

lara31 [8.8K]

Answer: you can use Pythagorean theorem , which formula is $a^{2} + b^{2} =c^{2}$ , "a" and "b" are the sides, and "c" is the hypotenuse (the longest side, the side opposite to the 90 degree angle)

<em>Example:</em>

If they give that one side is 2 inches and the other side is 4 and you need to find the hypotenuse it would be like this:

1) plug the numbers to the formula

$4^2 + 6^2 = c^{2}$

2) solve the exponents of the numbers given (not the letter, in this case "c")

16 + 36 = $c^2$

3) combine like terms (in this case 16 +36)

52 = $c^2$

4) Finally, Find the square root of "c" to remove its exponent and do the same to the other side, in this case 52)

$\sqrt{52} = \sqrt{c}$

(square root of 52 rounded to the nearest hundred is 7.21)

7.21 = c

<h3><u><em>So 7.21 is your missing side in this example</em></u></h3><h3>look up Pythagorean theorem Khan Academy</h3>

8 0

2 years ago

Kaleb went to a theme park with $25 to spend. He spent $5.25 on food and paid $4.00 for each ride. What was the greatest number

Shtirlitz [24]

Answer is 4 rides
19.75 after food so divide it by 4 to get your answer

8 0

2 years ago

Points H and F lie on circle c What is the length of line segment GH?

Nina [5.8K]

Answer:

6 units

Step-by-step explanation:

Given: Points H and F lie on circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.

To find: Length of GH.

Sol: EC = CH = 9 (Radius of the same circle are equal)

Now, GC = GH + CH

GC = GH + 9

Now In ΔEGC, using pythagoras theorem,

$(Hypotenuse)^{2} = (Base)^{2} +(Altitude)^{2}$ ......(ΔEGC is a right triangle)

$(GC)^{2} = (GE)^{2} +(EC)^{2}$

$(GH + 9)^{2} = (9)^{2} +(12)^{2}$

$(GH )^{2} + (9)^{2} + 18GH = 81 + 144$

$(GH )^{2} + 81 + 18GH = 81 + 144$

$(GH )^{2} + 18GH = 144$

Now, Let GH = <em>x</em>

$x^{2} +18x = 144$

On rearranging,

$x^{2} +18 x - 144 = 0$

$x^{2} - 6x +24x + 144 = 0$

$x (x-6) + 24 (x - 6) =0$

$(x - 6) (x + 24) = 0$

So x = 6 and x = - 24

∵ x cannot be - 24 as it will not satisfy the property of right triangle.

Therefore, the length of line segment GH = 6 units. so, Option (D) is the correct answer.

3 0

2 years ago

Read 2 more answers