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Dafna1 [17]
2 years ago
12

As Artemis Fowl's private jet approaches Heathrow airport, its horizontal distance from the airport is 22 miles when his altitud

e is 2.2 miles. To the nearest degree, what is the angle of descent of Artemis' plane?​

Mathematics
2 answers:
dezoksy [38]2 years ago
7 0

Answer:

The angle of descent of Artemis' plane is 6°

Step-by-step explanation:

Let

x -----> the angle of descent of Artemis' plane

we know that

The tangent of angle x is equal to divide the opposite side to angle x (altitude) by the adjacent side to angle x (horizontal distance)

see the attached figure to better understand the problem

so

tan(x)=2.2/22

x=arctan(2.2/22)=5.71°

Round to the nearest degree

x=6°

Murljashka [212]2 years ago
6 0

Answer:

The angle of descent of Artemis' plane is 6°

Step-by-step explanation:

You might be interested in
"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the
Citrus2011 [14]

Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

 Expected observed Diff

x p(x) p(x)*1000  

   

0 0.002 2  

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144  

5 0.189 189  

6 0.238 238  

7 0.178 178  

   

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.  

4 0
2 years ago
An American car travels 32 miles on one gallon of gas. A European car travels 12.7 kilometers on one liter of gas. Which car get
BabaBlast [244]
32 miles is the same as 19.8839 kilometers

There are 3.78541 liters in a gallon

Now we divide the two. 

19.8839 / 3.78541 ≈ 5.25

The American car gets 5.25 km per liter. So the European car is better on gas economy. 
5 0
2 years ago
Betty paints twice as fast as Dan. Working together, Dan and Betty can paint 2, 400 square feet in 4 hours. Another employee, Su
Natalija [7]

Answer:

2670 square feet. Option e.

Step-by-step explanation:

Dan and Betty can paint 2,400 square feet in 4 hours.

They can paint in one hour \frac{2400}{4} = 600 square feet.

Since given that Betty paints twice as fast as Dan. Let us take an equation:

Let Betty = B, Dan = D and Sue = S

B = 2D

4(B+D) = 2400

4B + 4D = 2400

12D = 2400

D = 200 sq. ft.

B = 2D = 400 sq. ft.

Therefore, Dan can paint 200 square feet in 1 hour and Betty paints twice 400 square feet in 1 hour.

Now given three of them can paint 3,600 square feet in 3 hours.

3( B+D+S) = 3600

3B + 3D + 3S = 3600

3(400) + 3(200) + 3(S) = 3600

1200 + 600 + 3S = 3600

S = 600 Sq. ft.

Sue can paint 600 square feet in one hour.

So sue can paint in 4 hours and 27 minutes.

(\frac{4+27}{60}) × 600

= 2670 square feet. Option e.

8 0
2 years ago
A contractor leans a 21-foot ladder against a building. The distance from the ground to the top of the ladder is 9 feet more tha
melomori [17]

Answer:

The distance from the ground to the top of the ladder = 18.7 feet

Step-by-step explanation:

The distance from the ground to the top of the ladder is 9 feet more than the distance from the building to the base of the ladder.

distance from the building to the base of the ladder.= X

The distance from the ground to the top of the ladder = 9+x

Solving the triangle using Pythagorean theorem

X² +(x+9)²= 21²

X² + x² + 18x +81= 441

2x² +18x -360 = 0

X² +9x -180 = 0

X= (-9-28.3)/2 or (-9+28.3)/2

Definitely x is going to be a positive number

So

X= (-9+28.3)/2

X=9.65 feet

The distance from the ground to the top of the ladder = 9+x

The distance from the ground to the top of the ladder = 9+9.65

The distance from the ground to the top of the ladder = 18.65

The distance from the ground to the top of the ladder = 18.7 feet

6 0
2 years ago
WILL GIVE BRANLIEST!!! Pls help! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the
iren [92.7K]

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

d=\sqrt{h^2+k^2}

Distance of P from ( -3, 4 ) :

d=\sqrt{(h+3)^2+(k-4)^2}

Now , these distance are equal :

h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2

Solving above equation , we get :

P=(\dfrac{16}{21},\dfrac{23}{7})

Hence , this is the required solution.

6 0
2 years ago
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