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2 years ago

Describe Sam's location relative to the theater

Mathematics

2 answers:

AVprozaik [17]2 years ago

7 0

What do you mean ? Is there a problem

sveticcg [70]2 years ago

3 0

Can you be a little more specific. Like where Sam lives and theater location.

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2 years ago

As part of a company incentive, each sales person that sells over \$40{,}000$40,000dollar sign, 40, comma, 000 in merchandise th

worty [1.4K]

Answer:

$58,600

Step-by-step explanation:

Data provided in the question:

Commission on Sales upto and including $40,000 = 5%

Commission on Sales above $40,000 = 10%

Total commission = $3,860

Now,

For sales of $40,000

maximum commission = 5% of $40,000

= $2,000

Since the commission received is greater than $2,000

Therefore,

The value of s is greater than $40,000

Thus

Amount qualifying for 10% commission = s - $40,000

therefore,

Total commission = $2,000 + 10% of (s - $40,000)

$3,860 = $2,000 + 0.10 × (s - $40,000)

$1,860 = 0.10 × (s - $40,000)

s - $40,000 = $18,600

s = $18,600 + $40,000

s = $58,600

4 0

2 years ago

Read 2 more answers

Two forces, F1 and F2, are represented by vectors with initial points that are at the origin. The first force has a magnitude of

Strike441 [17]

Answer:

Step-by-step explanation:

The two force F1 and F2 are represented by vectors with initial points that are at the origin.

the terminal point of the vector is point P(1, 1, 0)

Therefore, the direction of the vector force is

$v_1=(1-0)\hat i+(1-0)\hat j +(0-0)\hat k\\\\=1\hat i+1\hat j+0\hat k\\\\=\hat i + \hat j$

The unit vector in the direction of force will be

$\frac{v_1}{|v_1|} =\frac{\hat i+ \hat j}{\sqrt{1^2+1^2+0^2} } \\\\=\frac{1}{\sqrt{2} (\hat i +\hat j)}$

The magnitude of the force is 40lb, so the force will be

$F_1=40\times \frac{1}{\sqrt{2} } (\hat i+\hat j)\\\\=20\sqrt{2} (\hat i+\hat j)$

The terminal point of its vector is point Q(0, 1, 1)

Therefore, the direction of the vector force is

$v_2=(0-0)\hat i+(1-0)\hat j +(1-0)\hat k\\\\=0\hat i+1\hat j+1\hat k\\\\=\hat j + \hat k$

$\frac{v_2}{|v_2|} =\frac{\hat j+ \hat k}{\sqrt{0^2+1^2+1^2} } \\\\=\frac{1}{\sqrt{2} (\hat j +\hat k)}$

The magnitude of the force is 60lb, so the force will be

$F_2=60\times \frac{1}{\sqrt{2} } (\hat j+\hat k)\\\\=30\sqrt{2} (\hat j+\hat k)$

The resultant of the two forces is

$F=F_1+F_2\\\\=[20\sqrt{2} (\hat i+\hat j)]+[30\sqrt{2} (\hat j +\hat k)]\\\\=20\sqrt{2} \hat i+20\sqrt{2} \hat j +30\sqrt{2} \hat j+30\sqrt{2} \hat k\\\\=20\sqrt{2} \hat i+50\sqrt{2} \hat j+30\sqrt{2} \hat k$