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k0ka [10]
2 years ago
12

A trained sea lion slides from rest down a long

Physics
1 answer:
andrey2020 [161]2 years ago
5 0

Answer:

1.5 m/s²

Explanation:

Draw a free body diagram.  There are three forces acting on the sea lion: gravity pulling down, normal force perpendicular to the ramp, and friction parallel to the ramp.

Sum of the forces perpendicular to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the incline:

∑F = ma

mg sin θ − Nμ = ma

Substitute for N:

mg sin θ − (mg cos θ) μ = ma

g sin θ − g cos θ μ = a

a = g (sin θ − μ cos θ)

Given θ = 23° and μ = 0.26:

a = 9.8 (sin 23 − 0.26 cos 23)

a = 1.48

Rounded to two significant figures, the sea lion accelerates at 1.5 m/s².

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3 0
2 years ago
A rock of mass m is thrown horizontally off a building from a height h. the speed of the rock as it leaves the thrower's hand at
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The correct answer is <span>3) K_f =  \frac{1}{2}mv_0^2 + mgh.
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</span>E=U_i+K_i=mgh +  \frac{1}{2}mv_0^2
<span>As the rock falls down, its height h from the ground decreases, eventually reaching zero just before hitting the ground. This means that U, the potential energy just before hitting the ground, is zero, and the total final energy is just kinetic energy: 
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But for the law of conservation of energy, the total final energy must be equal to the tinitial energy, so E is always the same. Therefore, the final kinetic energy must be
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7 0
2 years ago
For this problem, imagine that you are on a ship that is oscillating up and down on a rough sea. Assume for simplicity that this
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Answer:

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Explanation:

7 0
2 years ago
The thrust of a certain boat’s engine generates a power of 10kW as the boat moves at constant speed 10ms through the water of a
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Answer:

The change in power is 4400 W.

Explanation:

Given that,

Power = 10 kW

Speed = 10 m/s

Increases speed = 12 m/s

Given equation is,

F=kv

We know that,

The power is,

P=Fv

Put the value of F into the formula

P=(kv)v

P=kv^2

P\propto v^2

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\dfrac{P}{P'}=\dfrac{v^2}{v'^2}

Put the value into the formula

\dfrac{10}{P'}=(\dfrac{10}{12})^2

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Using formula of change in power

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Put the value into the formula

\Delta P=14.4-10

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6 0
3 years ago
A 120-kg refrigerator that is 2.0 m tall and 85 cm wide has its center of mass at its geometrical center. You are attempting to
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To solve this problem it is necessary to apply the concepts related to Force of Friction and Torque given by the kinematic equations of motion.

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Replacing,

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6 0
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