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Harman [31]
2 years ago
3

A cross-section of an airplane wing is shown. Measurements of the thickness of the wing, in centimeters, at 16-centimeter interv

als are 6.1, 19.9, 26.7, 29.0, 27.2, 27.5, 23.6, 20.9, 15.8, 9.1, and 3.2. Use the Midpoint Rule with n = 5 to estimate the area of the wing's cross-section if a = 160. (Assume the thickness of the edges is nonzero.)
Answer has to be in cm^3
Mathematics
1 answer:
dem82 [27]2 years ago
5 0

Answer:

cross sectional area of the wing's is = 3404.8 cm²

Step-by-step explanation:

using n= 5 to estimate area of the wing's

a = 160

taking sum of thickness at n = 1, 3, 5, 7, 9

so sum of the measurement of the thickness at the given position

19.9 +29.0 + 27.5 +20.9 + 9.1 = 106.4

so the thickness is 106.4/5

           = 21.28 cm

cross sectional area of the wing's is = 160 × 21.28

                                                            = 3404.8 cm²

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<h2>Answer:</h2>

The ratios of earnings to hours are not the same each week, so the earnings do not vary directly with the hours.

<h2>Step-by-step explanation:</h2>

We know that the data points given by (x,y) are in direct variation if:

\dfrac{y}{x}=k  for each (x,y)

We are given data as:

Caleb’s Earnings Hours(x)        12          15         18         21

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So, we could see the ratio as:

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Hence, we could see that each ratio are not equal.

Hence, the relationship between the earnings and the number of hours does not represents a direct variation.

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2 years ago
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We are given the set of points
<span>{(1, 60), (2, 240), (3, 960), (4, 3840)}{(1, 60), (2, 240), (3, 960), (4, 3840)} 
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Substituting
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Answer:

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