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Wittaler [7]
2 years ago
15

Does the amount of heat absorbed as 1 kg of saturated liquid water boils to saturated vapor have to be equal to the amount of he

at released when 1 kg saturated water vapor condenses at 100 degrees Celsius? Explain
Engineering
1 answer:
alex41 [277]2 years ago
4 0

Answer:

Yes

Explanation:

The quantity of absorbed heat when one kilogram of liquid water which is saturated is boiled equals to the quantity of released heat when one kilogram of saturated water vapour condenses at 100 degree celcius because if they are not equal then some amount of excess energy can be created or can be destroyed from both the condensation and vapourization processes.

And this is a violation of thermodynamics first law.

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A 0.2-m^3 rigid tank equipped with a pressure regulator contains steam at 2MPa and 320C. The steam in the tank is now heated. Th
prohojiy [21]

Answer:

Q=486.49 KJ/kg

Explanation:

Given that

V= 0.2 m³

At initial condition

P= 2 MPa

T=320 °C

Final condition

P= 2 MPa

T=540°C

From steam table

At P= 2 MPa and T=320 °C

h₁=3070.15 KJ/kg

At P= 2 MPa and T=540°C

h₂=3556.64  KJ/kg

So the heat transfer ,Q=h₂ - h₁

Q= 3556.64 - 3070.15  KJ/kg

Q=486.49 KJ/kg

7 0
2 years ago
The 10-kg block slides down 2 m on the rough surface with kinetic friction coefficient μk = 0.2. What is the work done by the fr
Rashid [163]

Answer:

153.2 J

Explanation:

Let's first list our given parameters;

mass (m) of the block = 10 kg

which slides down ( i.e displacement) = 2 m

kinetic coefficient of friction (μk) = 0.2

In the diagram shown below;  if we take an integral look at the component of force in the direction of the displacement; we have

F_x= Fcos 40°

F_x= 100 (cos 40°)

F_x= 76.60 N

Workdone by the friction force can now be determined as:

W = F_x × displacement

W = 76.60 × 2

W = 153.2 J

∴  the work done by the friction force = 153.2 J

7 0
2 years ago
Radioactive wastes are temporarily stored in a spherical container, the center of which is buried a distance of 10 m below the e
puteri [66]

Given:

outer radius, R' = 10 m

inner diameter, d = 2 m

inner radius, R = \frac{d}{2} = 1 m

surface temperature, T' = 20^{\circ}C

Thermal conductivity of soil, K = 0.52 W/mK

Solution:

To calculate the thermal temperature of conductor, T, we know amount of heat, Q is given by :

Q =  \frac{T - T'}{\frac{R' - R}{4\pi KRR'}}

500 =  (T - 20)\frac{4\pi \times0.52\times 1\times 10}{10 - 1}

T = 68.86 +20 = 88.865^{\circ}C  

Therefore, outside surface temperature is 88.865^{\circ}C  

4 0
2 years ago
A person puts a few apples into the freezer at -15oC to cool them quickly for guests who are about to arrive. Initially, the app
frosja888 [35]

Answer:

Temperature at center of apples = 11.2⁰C

Temperature at surface of apples = 2.7⁰C

Amount of Heat transferred = 17.2kJ

Explanation:

The properties of apple are given as:

k = 0.418 W/m.°C

ρ = 840 kg/m³

Cр = 3.81 kJ/kg.°C

α = 1.3*10 ⁻⁷ m²/s

h = 8 W/m².°C

d = 0.09m

r = 0.045m

t = 1 hour = 3600s

<h2>Solution</h2>

Biot number is given as:

Bi = \frac{hr}{k}= \frac{8\cdot0.045}{0.418}=0.861

The constants λ₁ and A₁ corresponding to Biot number (from the table) are:

λ₁ = 1.476

A₁ = 1.239

Fourier Number is:

T = \frac{a\cdot{t}}{r^2} = \frac{(1.3\cdot10^{-7})(3600)}{0.045^2}= 0.231> 0.2

As Fourier Number > 0.2 , one term approximates solutions are applicable

The temperature at the center of apples, The temperature at surface of apples and Amount of heat transfer is found in the ATTACHMENT.

8 0
2 years ago
Initialize the tuple team_names with the strings 'Rockets', 'Raptors', 'Warriors', and 'Celtics' (The top-4 2018 NBA teams at th
Drupady [299]

Answer:

#Initialise a tuple

team_names = ('Rockets','Raptors','Warriors','Celtics')

print(team_names[0])

print(team_names[1])

print(team_names[2])

print(team_names[3])

Explanation:

The Python code illustrates or printed out the tuple team names at the end of a season.

The code displayed is a function that will display these teams as an output from the program.

4 0
2 years ago
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