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Dominik [7]
2 years ago
7

The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous ran- dom variable with a cumulat

ive distribution function ???? F(x)= 0, x<0, 1−e−4x, x≥0. Find the probability of waiting fewer than 12 minutes between successive speeders.
Mathematics
1 answer:
enyata [817]2 years ago
4 0

Answer: 0.5507

Step-by-step explanation:

Given : The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable X with a cumulative distribution function

F(x)= \begin{cases}0,& x

Since , the waiting time is in hours , then we can write 12 minutes as \dfrac{12}{60} hour i.e.0.2 hour.

Now, the probability of waiting fewer than 12 minutes between successive speeders is given by :-

P(X

Hence, the required probability = 0.5507

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On a road map, the locations A, B and C are collinear. Location C divides the road from location A to B, such that AC:CB = 1:2.
koban [17]

Answer:

C. (-1,-2)

Step-by-step explanation:

Since C internally divides AB in the ratio AC/CB = 1/2 = m/n where m = 1 and n = 2, we use the formula for internal division.

Let A = (x₁, y₁) = (5, 16), B = (x₂, y₂) and C = (x, y) = (3, 10)

So x = (mx₂ + nx₁)/(m + n)

y = (my₂ + ny₁)/(m + n)

Substituting the values of the coordinates, we have

x = (mx₂ + nx₁)/(m + n)

3 = (1 × x₂ + 2 × 5)/(2 + 1)

3 = (x₂ + 10)/3

multiplying through by 3, we have

9 = x₂ + 10

x₂ = 9 - 10

x₂ = -1

y = (my₂ + ny₁)/(m + n)

10 = (1 × y₂ + 2 × 16)/(2 + 1)

10 = (x₂ + 32)/3

multiplying through by 3, we have

30 = y₂ + 32

y₂ = 30 - 32

y₂ = -2

So, the coordinates of B are (-1, -2)

3 0
2 years ago
Craig has $1850 dollars in a bank account that he uses to make automatic payments of $400.73 on his car loan. If Craig stops mak
Ivenika [448]

Given:

Amount in the bank account = $1850

Monthly payment of can loan = $400.73

To find:

When would automatic payments make the value of the account zero?

Solution:

Craig stops making deposits to that account. So, amount $1850 in the bank account is used to make monthly payment of can loan.

On dividing the amount by monthly payment, we get

\dfrac{1850}{400.73}=4.61657

It means, the amount is sufficient for 4 payment but for the 5th payment the amount is not sufficient.

Therefore, the 5th automatic payments make the value of the account zero.

6 0
2 years ago
-6(2r +8)=-10(r-3)<br> I need the work to
barxatty [35]

Answer:

r = -39

Step-by-step explanation:

So we are trying to solve the equation for r.

-6(2r + 8) = -10(r - 3)

Divide both sides by -2. (This will make distributing much easier.)

3(2r + 8) = 5(r - 3)

Distribute the 3 on the left side and the 5 on the right side,

6r + 24 = 5r - 15

Subtract 24 from both sides.

6r = 5r - 39

Subtract 5r from both sides.

r = -39

So now we have solve the equation.

I hope you find my answer and explanation to be helpful. Happy studying. :)

5 0
2 years ago
The spelling contest awards four prizes Tim,Sam,Jen, and Kate all made it to the final round. In how many ways can first, second
topjm [15]
It is the 3 one correct me if im wrong 
7 0
2 years ago
Enter the values for the variables that give the correct simplified expressions, x = ≥ 0.
ELEN [110]

Answer:

b= 2x²; c = 4; 3 = 3 ; g = 6x

Step-by-step explanation:

\textbf{(1)}\\\sqrt{50{x}^{2} } = \sqrt{25\times2x^{2}} = 5\times \mathbf{\sqrt{2x^{2}}}\\\textbf{b = 2x}^{2}\\\\\textbf{(2)}\\\sqrt{32x} = \sqrt{16 \times 2x} = \mathbf{4}\times \sqrt{2x}\\\textbf{c = 4}\\\\\textbf{(3)}\\\sqrt{18n} = \sqrt{9 \times 2n} = \mathbf{3}\times \sqrt{2n}\\\textbf{e = 3}\\\\\textbf{(4)}\\\sqrt{72x^{2}} = \sqrt{36 \times 2x^{2}} = 6\times \sqrt{2} \times x\\= \mathbf{6x}\sqrt{2}\\\textbf{g = 6x}

3 0
2 years ago
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