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2 years ago

Identify the graph and describe the solution set of this system of inequalities. Y<-3x-2 y>-3x+8

Mathematics

1 answer:

zubka84 [21]2 years ago

3 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y < -3x-2 -----> inequality A

The solution of the inequality A is the shaded area below the dashed line y=-3x-2

The slope of the dashed line is negative m=-3

The-y-intercept of the dashed line is (0,-2)

The x-intercept of the dashed line is (-0.67,0)

y > -3x+8 -----> inequality B

The solution of the inequality B is the shaded area above the dashed line y=-3x+8

The slope of the dashed line is negative m=-3

The-y-intercept of the dashed line is (0,8)

The x-intercept of the dashed line is (2.67,0)

using a graphing tool

The system of inequalities y < -3x-2 and y > -3x+8 has no solution (parallel lines)

see the attached figure

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I will rewrite the question for better understanding:

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighborhood. It takes Ashley 2/3 of a minute to prepare one bag. It takes each of her friends 75% longer to prepare a bag. How many hours will it take Ashley and 4 of her friends to prepare 1575 bags of samples?

Answer:

5.3 hours

Explanation:

1) Time it takes Ashley to preprate one bag:

2/3 min

2) Time it takes each friend of Ashley: 75% more than 2/3 min

75% × 2/3 min = 0.75 × 2/3 min = 3/4 × 2/3 min= 2/4 min = 1/2 min = 0.5 min

2/3 min + 1/2 min = 7/6 min

3) Time it takes Ashley and the 4 friends working along to prepare one bag:

Convert each time into a rate, since you can set that the total rate of Ashley along with her four friends is equal to the sum of each rate:

Rate of Ashley: 1 bag / (2/3) min = 3/2 bag/min

Rate of each friend: 1 bag / (7/6) min = 6/7 bag/min

Rate of Ashley and 4 friends = 3/2 bag/min + 4 × 6/7 bag/min = (3/2 +24/7) bag/min = 69/14 bag/min

4) Time of prepare 1575 bags of samples:

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1 year ago

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1 year ago

The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin

Free_Kalibri [48]

Answer:

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Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

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Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.03

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$P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03$

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Calculation the value from standard normal z table, we have,

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Thus, 7.90 separates the bottom 3% of the weights.

Thus, the correct answer is

Option D) 7.90 g and 8.12 g

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