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2 years ago

Identify the graph and describe the solution set of this system of inequalities. Y<-3x-2 y>-3x+8

Mathematics

1 answer:

zubka84 [21]2 years ago

3 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y < -3x-2 -----> inequality A

The solution of the inequality A is the shaded area below the dashed line y=-3x-2

The slope of the dashed line is negative m=-3

The-y-intercept of the dashed line is (0,-2)

The x-intercept of the dashed line is (-0.67,0)

y > -3x+8 -----> inequality B

The solution of the inequality B is the shaded area above the dashed line y=-3x+8

The slope of the dashed line is negative m=-3

The-y-intercept of the dashed line is (0,8)

The x-intercept of the dashed line is (2.67,0)

using a graphing tool

The system of inequalities y < -3x-2 and y > -3x+8 has no solution (parallel lines)

see the attached figure

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2 years ago

Mrs. Nestler enjoys listening to classical music. She has the following audio CDs by her favorite composers in her collection: 4

ivolga24 [154]

Answer:

10.55% probability

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the CDs are chosen is not important. So we use the combinations formula to solve this question.

1 Bach CD, from a set of 4.

1 Beethoven CD, from a set of 6.

1 Brahms CD, from a set of 3.

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2 years ago

Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b

Aloiza [94]

Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

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