Question

PLZ HELP!!!Solve the equation, and enter the solutions from least to greatest. If there is only one solution, enter “n.a.” for the second solution.

Answer 1

Answer:

x = 0

x = 2

Step-by-step explanation:

We cross multiply and do algebra and solve for x:

$\frac{x}{2x-3}=\frac{3x}{x+1}\\x(x+1)=3x(2x-3)\\x^2+x=6x^2-9x\\10x=5x^2\\5x^2-10x=0\\5x(x-2)=0\\x=0,2$

Hence, the solutions are

x = 0

and

x = 2